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Masahiro Yamada authored
$(filter -i,$(MAKEFLAGS)) works only in limited use-cases. The representation of $(MAKEFLAGS) depends on various factors: - GNU Make version (version 3.8x or version 4.x) - The presence of other flags like -j In my experiments, $(MAKEFLAGS) is expanded as follows: * GNU Make 3.8x: * without -j option: --no-print-directory -Rri * with -j option: --no-print-directory -Rr --jobserver-fds=3,4 -j -i * GNU Make 4.x: * without -j option: irR --no-print-directory * with -j option: irR -j --jobserver-fds=3,4 --no-print-directory For GNU Make 4.x, the flags are grouped as 'irR', which does not work. For the single thread build with GNU Make 3.8x, the flags are grouped as '-Rri', which does not work either. To make it work for all cases, do likewise as commit 6f0fa58e ("kbuild: simplify silent build (-s) detection"). BTW, since commit ff9b45c5 ("kbuild: modpost: read modules.order instead of $(MODVERDIR)/*.mod"), you also need to pass -k option to build final *.ko files. 'make -i -k' ignores compile errors in modules, and build as many remaining *.ko as possible. Please note this feature is kind of dangerous if other modules depend on the broken module because the generated modules will lack the correct module dependency or CRC. Honestly, I am not a big fan of it, but I am keeping this feature. Fixes: eed380f3 ("modpost: Optionally ignore secondary errors seen if a single module build fails") Cc: Guenter Roeck <linux@roeck-us.net> Signed-off-by: Masahiro Yamada <masahiroy@kernel.org>
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