be more optimistic when parsing optional keywords: if (interned) string...

be more optimistic when parsing optional keywords: if (interned) string pointers are identical, we know it's the right type of object

Cython/Compiler/Nodes.py

@@ -4961,18 +4961,17 @@ static int __Pyx_ParseOptionalKeywords(
     PyObject*** first_kw_arg = argnames + num_pos_args;
 
     while (PyDict_Next(kwds, &pos, &key, &value)) {
+        name = first_kw_arg;
+        while (*name && (**name != key)) name++;
+        if (*name) {
+            values[name-argnames] = value;
+        } else {
             #if PY_MAJOR_VERSION < 3
             if (unlikely(!PyString_CheckExact(key)) && unlikely(!PyString_Check(key))) {
             #else
             if (unlikely(!PyUnicode_CheckExact(key)) && unlikely(!PyUnicode_Check(key))) {
             #endif
                 goto invalid_keyword_type;
-        } else {
-            name = argnames;
-            while (*name && (**name != key)) name++;
-            if (*name) {
-                if (name < first_kw_arg) goto arg_passed_twice;
-                values[name-argnames] = value;
             } else {
                 for (name = first_kw_arg; *name; name++) {
                     #if PY_MAJOR_VERSION >= 3