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Gwenaël Samain
cython
Commits
e3651b15
Commit
e3651b15
authored
Jun 16, 2018
by
scoder
Committed by
GitHub
Jun 16, 2018
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Merge pull request #2360 from gabrieldemarmiesse/test_profiling_tutorial_5
Added tests to "profiling tutorial" part 5
parents
ce64b3b6
ad096ace
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docs/examples/tutorial/profiling_tutorial/calc_pi_4.pyx
docs/examples/tutorial/profiling_tutorial/calc_pi_4.pyx
+16
-0
docs/src/tutorial/profiling_tutorial.rst
docs/src/tutorial/profiling_tutorial.rst
+2
-17
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docs/examples/tutorial/profiling_tutorial/calc_pi_4.pyx
0 → 100644
View file @
e3651b15
# cython: profile=True
# calc_pi.pyx
cimport
cython
@
cython
.
profile
(
False
)
cdef
inline
double
recip_square
(
int
i
):
return
1.
/
(
i
*
i
)
def
approx_pi
(
int
n
=
10000000
):
cdef
double
val
=
0.
cdef
int
k
for
k
in
range
(
1
,
n
+
1
):
val
+=
recip_square
(
k
)
return
(
6
*
val
)
**
.
5
docs/src/tutorial/profiling_tutorial.rst
View file @
e3651b15
...
@@ -238,24 +238,9 @@ That bought us another 1.8 seconds. Not the dramatic change we could have
...
@@ -238,24 +238,9 @@ That bought us another 1.8 seconds. Not the dramatic change we could have
expected. And why is recip_square still in this table; it is supposed to be
expected. And why is recip_square still in this table; it is supposed to be
inlined, isn't it? The reason for this is that Cython still generates profiling code
inlined, isn't it? The reason for this is that Cython still generates profiling code
even if the function call is eliminated. Let's tell it to not
even if the function call is eliminated. Let's tell it to not
profile recip_square any more; we couldn't get the function to be much faster anyway:
:
profile recip_square any more; we couldn't get the function to be much faster anyway:
# encoding: utf-8
.. literalinclude:: ../../examples/tutorial/profiling_tutorial/calc_pi_4.pyx
# cython: profile=True
# filename: calc_pi.pyx
cimport cython
@cython.profile(False)
cdef inline double recip_square(int i):
return 1./(i*i)
def approx_pi(int n=10000000):
cdef double val = 0.
cdef int k
for k in xrange(1,n+1):
val += recip_square(k)
return (6 * val)**.5
Running this shows an interesting result:
Running this shows an interesting result:
...
...
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