btrfs: include the free space tree in the global rsv minimum calculation

Filipe reported a problem where generic/619 was failing with an ENOSPC
abort while running delayed refs, like the following

  BTRFS: Transaction aborted (error -28)
  WARNING: CPU: 3 PID: 522920 at fs/btrfs/free-space-tree.c:1049 add_to_free_space_tree+0xe5/0x110 [btrfs]
  CPU: 3 PID: 522920 Comm: kworker/u16:19 Tainted: G        W         5.16.0-rc2-btrfs-next-106 #1
  Hardware name: QEMU Standard PC (i440FX + PIIX, 1996), BIOS rel-1.14.0-0-g155821a1990b-prebuilt.qemu.org 04/01/2014
  Workqueue: events_unbound btrfs_async_reclaim_metadata_space [btrfs]
  RIP: 0010:add_to_free_space_tree+0xe5/0x110 [btrfs]
  RSP: 0000:ffffa65087fb7b20 EFLAGS: 00010282
  RAX: 0000000000000000 RBX: 0000000000001000 RCX: 0000000000000000
  RDX: 0000000000000001 RSI: ffffffff9131eeaa RDI: 00000000ffffffff
  RBP: ffff8d62e26481b8 R08: ffffffff9ad97ce0 R09: 0000000000000001
  R10: 0000000000000000 R11: 0000000000000001 R12: 00000000ffffffe4
  R13: ffff8d61c25fe688 R14: ffff8d61ebd88800 R15: ffff8d61ebd88a90
  FS:  0000000000000000(0000) GS:ffff8d64ed400000(0000) knlGS:0000000000000000
  CS:  0010 DS: 0000 ES: 0000 CR0: 0000000080050033
  CR2: 00007fa46a8b1000 CR3: 0000000148d18003 CR4: 0000000000370ee0
  DR0: 0000000000000000 DR1: 0000000000000000 DR2: 0000000000000000
  DR3: 0000000000000000 DR6: 00000000fffe0ff0 DR7: 0000000000000400
  Call Trace:
   <TASK>
   __btrfs_free_extent+0x516/0x950 [btrfs]
   __btrfs_run_delayed_refs+0x2b1/0x1250 [btrfs]
   btrfs_run_delayed_refs+0x86/0x210 [btrfs]
   flush_space+0x403/0x630 [btrfs]
   ? call_rcu_tasks_generic+0x50/0x80
   ? lock_release+0x223/0x4a0
   ? btrfs_get_alloc_profile+0xb5/0x290 [btrfs]
   ? do_raw_spin_unlock+0x4b/0xa0
   btrfs_async_reclaim_metadata_space+0x139/0x320 [btrfs]
   process_one_work+0x24c/0x5b0
   worker_thread+0x55/0x3c0
   ? process_one_work+0x5b0/0x5b0
   kthread+0x17c/0x1a0
   ? set_kthread_struct+0x40/0x40
   ret_from_fork+0x22/0x30

There's a couple of reasons for this, but in generic/619's case the
largest reason is because it is a very small file system, ad we do not
reserve enough space for the global reserve.

With the free space tree we now have the free space tree that we need to
modify when running delayed refs.  This means we need the global reserve
to take this into account when it calculates the minimum size it needs
to be.  This is especially important for very small file systems.

Fix this by adjusting the minimum global block rsv size math to include
the size of the free space tree when calculating the size.
Reviewed-by: Nikolay Borisov <nborisov@suse.com>
Signed-off-by: Josef Bacik <josef@toxicpanda.com>
Signed-off-by: David Sterba <dsterba@suse.com>

fs/btrfs/block-rsv.c

@@ -352,25 +352,29 @@ void btrfs_update_global_block_rsv(struct btrfs_fs_info *fs_info)
 {
 	struct btrfs_block_rsv *block_rsv = &fs_info->global_block_rsv;
 	struct btrfs_space_info *sinfo = block_rsv->space_info;
-	struct btrfs_root *extent_root = btrfs_extent_root(fs_info, 0);
-	struct btrfs_root *csum_root = btrfs_csum_root(fs_info, 0);
-	u64 num_bytes;
-	unsigned min_items;
+	struct btrfs_root *root, *tmp;
+	u64 num_bytes = btrfs_root_used(&fs_info->tree_root->root_item);
+	unsigned int min_items = 1;
 
 	/*
 	 * The global block rsv is based on the size of the extent tree, the
 	 * checksum tree and the root tree.  If the fs is empty we want to set
 	 * it to a minimal amount for safety.
+	 *
+	 * We also are going to need to modify the minimum of the tree root and
+	 * any global roots we could touch.
 	 */
-	num_bytes = btrfs_root_used(&extent_root->root_item) +
-		btrfs_root_used(&csum_root->root_item) +
-		btrfs_root_used(&fs_info->tree_root->root_item);
-
-	/*
-	 * We at a minimum are going to modify the csum root, the tree root, and
-	 * the extent root.
-	 */
-	min_items = 3;
+	read_lock(&fs_info->global_root_lock);
+	rbtree_postorder_for_each_entry_safe(root, tmp, &fs_info->global_root_tree,
+					     rb_node) {
+		if (root->root_key.objectid == BTRFS_EXTENT_TREE_OBJECTID ||
+		    root->root_key.objectid == BTRFS_CSUM_TREE_OBJECTID ||
+		    root->root_key.objectid == BTRFS_FREE_SPACE_TREE_OBJECTID) {
+			num_bytes += btrfs_root_used(&root->root_item);
+			min_items++;
+		}
+	}
+	read_unlock(&fs_info->global_root_lock);
 
 	/*
 	 * But we also want to reserve enough space so we can do the fallback