pwm: lpss-platform: Convert to platform remove callback returning void

The .remove() callback for a platform driver returns an int which makes
many driver authors wrongly assume it's possible to do error handling by
returning an error code. However the value returned is (mostly) ignored
and this typically results in resource leaks. To improve here there is a
quest to make the remove callback return void. In the first step of this
quest all drivers are converted to .remove_new() which already returns
void.

Trivially convert this driver from always returning zero in the remove
callback to the void returning variant.
Signed-off-by: Uwe Kleine-König <u.kleine-koenig@pengutronix.de>
Signed-off-by: Thierry Reding <thierry.reding@gmail.com>

drivers/pwm/pwm-lpss-platform.c

@@ -62,10 +62,9 @@ static int pwm_lpss_probe_platform(struct platform_device *pdev)
 	return 0;
 }
 
-static int pwm_lpss_remove_platform(struct platform_device *pdev)
+static void pwm_lpss_remove_platform(struct platform_device *pdev)
 {
 	pm_runtime_disable(&pdev->dev);
-	return 0;
 }
 
 static const struct acpi_device_id pwm_lpss_acpi_match[] = {
@@ -83,7 +82,7 @@ static struct platform_driver pwm_lpss_driver_platform = {
 		.acpi_match_table = pwm_lpss_acpi_match,
 	},
 	.probe = pwm_lpss_probe_platform,
-	.remove = pwm_lpss_remove_platform,
+	.remove_new = pwm_lpss_remove_platform,
 };
 module_platform_driver(pwm_lpss_driver_platform);