Commit c933505d authored by hf@deer.(none)'s avatar hf@deer.(none)

Fix for bug #3874 (Group by field is not considered)

parent 58c64aea
...@@ -2441,3 +2441,39 @@ a c ...@@ -2441,3 +2441,39 @@ a c
SELECT a, b AS c FROM t1 ORDER BY b+1; SELECT a, b AS c FROM t1 ORDER BY b+1;
a c a c
drop table t1; drop table t1;
DROP TABLE IF EXISTS t1, t2;
CREATE TABLE t1 ( a INT NOT NULL, b INT NOT NULL, UNIQUE idx (a,b) );
INSERT INTO t1 VALUES (1,1),(1,2),(1,3),(1,4);
CREATE TABLE t2 ( a INT NOT NULL, b INT NOT NULL, c INT );
INSERT INTO t2 VALUES ( 1,10,1), (1,10,2), (1,11,1), (1,11,2), (1,2,1), (1,2,2),
(1,2,3);
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY a, b, c;
a b c d
1 2 1 1
1 2 2 1
1 2 3 1
1 10 2
1 11 2
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY t1.a, t1.b, c;
a b c d
1 10 4
1 2 1 1
1 2 2 1
1 2 3 1
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY t2.a, t2.b, c;
a b c d
1 2 1 1
1 2 2 1
1 2 3 1
1 10 2
1 11 2
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2,t1
WHERE t2.a = t1.a AND t2.b = t1.b GROUP BY a, b, c;
a b c d
1 2 1 1
1 2 2 1
1 2 3 1
DROP TABLE IF EXISTS t1, t2;
...@@ -1992,3 +1992,24 @@ CREATE TABLE t1 (a INT, b INT); ...@@ -1992,3 +1992,24 @@ CREATE TABLE t1 (a INT, b INT);
SELECT a, b AS c FROM t1 ORDER BY c+1; SELECT a, b AS c FROM t1 ORDER BY c+1;
SELECT a, b AS c FROM t1 ORDER BY b+1; SELECT a, b AS c FROM t1 ORDER BY b+1;
drop table t1; drop table t1;
#
# Bug #3874 (function in GROUP and LEFT JOIN)
#
DROP TABLE IF EXISTS t1, t2;
CREATE TABLE t1 ( a INT NOT NULL, b INT NOT NULL, UNIQUE idx (a,b) );
INSERT INTO t1 VALUES (1,1),(1,2),(1,3),(1,4);
CREATE TABLE t2 ( a INT NOT NULL, b INT NOT NULL, c INT );
INSERT INTO t2 VALUES ( 1,10,1), (1,10,2), (1,11,1), (1,11,2), (1,2,1), (1,2,2),
(1,2,3);
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY a, b, c;
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY t1.a, t1.b, c;
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2 LEFT JOIN
t1 ON t2.a = t1.a AND t2.b = t1.b GROUP BY t2.a, t2.b, c;
SELECT t2.a, t2.b, IF(t1.b IS NULL,'',c) AS c, COUNT(*) AS d FROM t2,t1
WHERE t2.a = t1.a AND t2.b = t1.b GROUP BY a, b, c;
DROP TABLE IF EXISTS t1, t2;
...@@ -3115,7 +3115,7 @@ eq_ref_table(JOIN *join, ORDER *start_order, JOIN_TAB *tab) ...@@ -3115,7 +3115,7 @@ eq_ref_table(JOIN *join, ORDER *start_order, JOIN_TAB *tab)
tab->cached_eq_ref_table=1; tab->cached_eq_ref_table=1;
if (tab->type == JT_CONST) // We can skip const tables if (tab->type == JT_CONST) // We can skip const tables
return (tab->eq_ref_table=1); /* purecov: inspected */ return (tab->eq_ref_table=1); /* purecov: inspected */
if (tab->type != JT_EQ_REF) if (tab->type != JT_EQ_REF || tab->table->maybe_null)
return (tab->eq_ref_table=0); // We must use this return (tab->eq_ref_table=0); // We must use this
Item **ref_item=tab->ref.items; Item **ref_item=tab->ref.items;
Item **end=ref_item+tab->ref.key_parts; Item **end=ref_item+tab->ref.key_parts;
......
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