eeepc-laptop: flatten control flow

In eeepc_rfkill_hotplug there's an if statement with a big tail that
ends right before the out_unlock label. We might as well invert the
condition and jump to out_unlock in that case, pretty much like the rest
of the code does. This removes an indentation level for a large chunk of
code and also stops suggesting there might be an else clause.
Signed-off-by: Frans Klaver <fransklaver@gmail.com>
Signed-off-by: Darren Hart <dvhart@linux.intel.com>

drivers/platform/x86/eeepc-laptop.c

@@ -580,7 +580,9 @@ static void eeepc_rfkill_hotplug(struct eeepc_laptop *eeepc, acpi_handle handle)
 	mutex_lock(&eeepc->hotplug_lock);
 	pci_lock_rescan_remove();
 
-	if (eeepc->hotplug_slot) {
+	if (!eeepc->hotplug_slot)
+		goto out_unlock;
+
 	port = acpi_get_pci_dev(handle);
 	if (!port) {
 		pr_warning("Unable to find port\n");
@@ -632,7 +634,6 @@ static void eeepc_rfkill_hotplug(struct eeepc_laptop *eeepc, acpi_handle handle)
 	}
 out_put_dev:
 	pci_dev_put(port);
-	}
 
 out_unlock:
 	pci_unlock_rescan_remove();