Commit a4906ea0 authored by Sathya Perla's avatar Sathya Perla Committed by David S. Miller

be2net: define macro for_all_tx_queues_on_eq()

Replace the for() loop that traverses all the TX queues on an EQ
with the macro for_all_tx_queues_on_eq(). With this expalnatory
name, the one line comment is not required anymore.
Signed-off-by: default avatarSathya Perla <sathya.perla@emulex.com>
Signed-off-by: default avatarDavid S. Miller <davem@davemloft.net>
parent c8f64615
...@@ -621,6 +621,10 @@ extern const struct ethtool_ops be_ethtool_ops; ...@@ -621,6 +621,10 @@ extern const struct ethtool_ops be_ethtool_ops;
for (i = eqo->idx, rxo = &adapter->rx_obj[i]; i < adapter->num_rx_qs;\ for (i = eqo->idx, rxo = &adapter->rx_obj[i]; i < adapter->num_rx_qs;\
i += adapter->num_evt_qs, rxo += adapter->num_evt_qs) i += adapter->num_evt_qs, rxo += adapter->num_evt_qs)
#define for_all_tx_queues_on_eq(adapter, eqo, txo, i) \
for (i = eqo->idx, txo = &adapter->tx_obj[i]; i < adapter->num_tx_qs;\
i += adapter->num_evt_qs, txo += adapter->num_evt_qs)
#define is_mcc_eqo(eqo) (eqo->idx == 0) #define is_mcc_eqo(eqo) (eqo->idx == 0)
#define mcc_eqo(adapter) (&adapter->eq_obj[0]) #define mcc_eqo(adapter) (&adapter->eq_obj[0])
......
...@@ -2503,12 +2503,12 @@ int be_poll(struct napi_struct *napi, int budget) ...@@ -2503,12 +2503,12 @@ int be_poll(struct napi_struct *napi, int budget)
struct be_adapter *adapter = eqo->adapter; struct be_adapter *adapter = eqo->adapter;
int max_work = 0, work, i, num_evts; int max_work = 0, work, i, num_evts;
struct be_rx_obj *rxo; struct be_rx_obj *rxo;
struct be_tx_obj *txo;
num_evts = events_get(eqo); num_evts = events_get(eqo);
/* Process all TXQs serviced by this EQ */ for_all_tx_queues_on_eq(adapter, eqo, txo, i)
for (i = eqo->idx; i < adapter->num_tx_qs; i += adapter->num_evt_qs) be_process_tx(adapter, txo, i);
be_process_tx(adapter, &adapter->tx_obj[i], i);
if (be_lock_napi(eqo)) { if (be_lock_napi(eqo)) {
/* This loop will iterate twice for EQ0 in which /* This loop will iterate twice for EQ0 in which
......
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