expose existance of CodeType, but leave its value as None

b71d7063 · Chris Toshok · 50143e43 · b71d7063
Commit b71d7063 authored Mar 13, 2015 by Chris Toshok
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from_cpython/Lib/types.py from_cpython/Lib/types.py +1 -0

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--- a/from_cpython/Lib/types.py
+++ b/from_cpython/Lib/types.py
@@ -45,6 +45,7 @@ FunctionType = type(_f)
 LambdaType = type(lambda: None)         # Same as FunctionType
 # Pyston change: there is no concept of a "code object" yet:
 # CodeType = type(_f.func_code)
+CodeType = None

 def _g():
    yield 1