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Kirill Smelkov
cpython
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0e15a6e2
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0e15a6e2
authored
Apr 17, 2012
by
Raymond Hettinger
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Clarify that a new connection needs to be made after the close.
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Doc/library/sqlite3.rst
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0e15a6e2
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@@ -51,6 +51,12 @@ Usually your SQL operations will need to use values from Python variables. You
shouldn't assemble your query using Python's string operations because doing so
is insecure; it makes your program vulnerable to an SQL injection attack.
The data you've saved is persistent and is available in subsequent sessions::
import sqlite3
conn = sqlite3.connect('/tmp/example')
c = conn.cursor()
Instead, use the DB-API's parameter substitution. Put ``?`` as a placeholder
wherever you want to use a value, and then provide a tuple of values as the
second argument to the cursor's :meth:`~Cursor.execute` method. (Other database
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