Commit 19f72e77 authored by Georg Brandl's avatar Georg Brandl

Fix two mp doc issues from #4012.

parent 5fbc2f2d
......@@ -232,7 +232,7 @@ For example::
if __name__ == '__main__':
pool = Pool(processes=4) # start 4 worker processes
result = pool.applyAsync(f, [10]) # evaluate "f(10)" asynchronously
result = pool.apply_async(f, [10]) # evaluate "f(10)" asynchronously
print(result.get(timeout=1)) # prints "100" unless your computer is *very* slow
print(pool.map(f, range(10))) # prints "[0, 1, 4,..., 81]"
......@@ -1505,7 +1505,7 @@ with the :class:`Pool` class.
The class of the result returned by :meth:`Pool.apply_async` and
:meth:`Pool.map_async`.
.. method:: get([timeout)
.. method:: get([timeout])
Return the result when it arrives. If *timeout* is not ``None`` and the
result does not arrive within *timeout* seconds then
......@@ -1535,7 +1535,7 @@ The following example demonstrates the use of a pool::
if __name__ == '__main__':
pool = Pool(processes=4) # start 4 worker processes
result = pool.applyAsync(f, (10,)) # evaluate "f(10)" asynchronously
result = pool.apply_async(f, (10,)) # evaluate "f(10)" asynchronously
print(result.get(timeout=1)) # prints "100" unless your computer is *very* slow
print(pool.map(f, range(10))) # prints "[0, 1, 4,..., 81]"
......@@ -1546,7 +1546,7 @@ The following example demonstrates the use of a pool::
print(it.next(timeout=1)) # prints "4" unless your computer is *very* slow
import time
result = pool.applyAsync(time.sleep, (10,))
result = pool.apply_async(time.sleep, (10,))
print(result.get(timeout=1)) # raises TimeoutError
......
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