Skip to content
Projects
Groups
Snippets
Help
Loading...
Help
Support
Keyboard shortcuts
?
Submit feedback
Contribute to GitLab
Sign in / Register
Toggle navigation
C
cpython
Project overview
Project overview
Details
Activity
Releases
Repository
Repository
Files
Commits
Branches
Tags
Contributors
Graph
Compare
Issues
0
Issues
0
List
Boards
Labels
Milestones
Merge Requests
0
Merge Requests
0
Analytics
Analytics
Repository
Value Stream
Wiki
Wiki
Members
Members
Collapse sidebar
Close sidebar
Activity
Graph
Create a new issue
Commits
Issue Boards
Open sidebar
Kirill Smelkov
cpython
Commits
4ffe9a06
Commit
4ffe9a06
authored
Aug 15, 2012
by
Sandro Tosi
Browse files
Options
Browse Files
Download
Email Patches
Plain Diff
clarify in/not in in case of infinite iterators; thanks to Sergey Skovorodkin from docs@
parent
c7b8f809
Changes
1
Hide whitespace changes
Inline
Side-by-side
Showing
1 changed file
with
2 additions
and
2 deletions
+2
-2
Doc/howto/functional.rst
Doc/howto/functional.rst
+2
-2
No files found.
Doc/howto/functional.rst
View file @
4ffe9a06
...
@@ -244,9 +244,9 @@ Built-in functions such as :func:`max` and :func:`min` can take a single
...
@@ -244,9 +244,9 @@ Built-in functions such as :func:`max` and :func:`min` can take a single
iterator argument and will return the largest or smallest element. The ``"in"``
iterator argument and will return the largest or smallest element. The ``"in"``
and ``"not in"`` operators also support iterators: ``X in iterator`` is true if
and ``"not in"`` operators also support iterators: ``X in iterator`` is true if
X is found in the stream returned by the iterator. You'll run into obvious
X is found in the stream returned by the iterator. You'll run into obvious
problems if the iterator is infinite; ``max()``, ``min()``
, and ``"not in"``
problems if the iterator is infinite; ``max()``, ``min()``
will never return, and if the element X never appears in the stream, the
will never return, and if the element X never appears in the stream, the
``"in"``
operator
won't return either.
``"in"``
and ``"not in"`` operators
won't return either.
Note that you can only go forward in an iterator; there's no way to get the
Note that you can only go forward in an iterator; there's no way to get the
previous element, reset the iterator, or make a copy of it. Iterator objects
previous element, reset the iterator, or make a copy of it. Iterator objects
...
...
Write
Preview
Markdown
is supported
0%
Try again
or
attach a new file
Attach a file
Cancel
You are about to add
0
people
to the discussion. Proceed with caution.
Finish editing this message first!
Cancel
Please
register
or
sign in
to comment