Commit a27c8e37 authored by Éric Araujo's avatar Éric Araujo

Branch merge

parents d6dcf826 b22e17b2
......@@ -138,7 +138,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
# let's see what the server received : we should
# have 2 similar requests
self.assertTrue(self.conn.reqs, 2)
self.assertEqual(len(self.conn.reqs), 2)
req1 = dict(self.conn.reqs[0].headers)
req2 = dict(self.conn.reqs[1].headers)
self.assertEqual(req2['Content-length'], req1['Content-length'])
......@@ -168,7 +168,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
del register_module.raw_input
# we should have send a request
self.assertTrue(self.conn.reqs, 1)
self.assertEqual(len(self.conn.reqs), 1)
req = self.conn.reqs[0]
headers = dict(req.headers)
self.assertEqual(headers['Content-length'], '608')
......@@ -186,7 +186,7 @@ class RegisterTestCase(PyPIRCCommandTestCase):
del register_module.raw_input
# we should have send a request
self.assertTrue(self.conn.reqs, 1)
self.assertEqual(len(self.conn.reqs), 1)
req = self.conn.reqs[0]
headers = dict(req.headers)
self.assertEqual(headers['Content-length'], '290')
......
......@@ -178,7 +178,7 @@ def heappushpop(heap, item):
return item
def heapify(x):
"""Transform list into a heap, in-place, in O(len(heap)) time."""
"""Transform list into a heap, in-place, in O(len(x)) time."""
n = len(x)
# Transform bottom-up. The largest index there's any point to looking at
# is the largest with a child index in-range, so must have 2*i + 1 < n,
......@@ -368,7 +368,7 @@ def nsmallest(n, iterable, key=None):
return [min(chain(head, it))]
return [min(chain(head, it), key=key)]
# When n>=size, it's faster to use sort()
# When n>=size, it's faster to use sorted()
try:
size = len(iterable)
except (TypeError, AttributeError):
......@@ -406,7 +406,7 @@ def nlargest(n, iterable, key=None):
return [max(chain(head, it))]
return [max(chain(head, it), key=key)]
# When n>=size, it's faster to use sort()
# When n>=size, it's faster to use sorted()
try:
size = len(iterable)
except (TypeError, AttributeError):
......
......@@ -639,7 +639,6 @@ def get_platform():
m = re.search(
r'<key>ProductUserVisibleVersion</key>\s*' +
r'<string>(.*?)</string>', f.read())
f.close()
if m is not None:
macrelease = '.'.join(m.group(1).split('.')[:2])
# else: fall back to the default behaviour
......
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