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Kirill Smelkov
cpython
Commits
b5bc33cd
Commit
b5bc33cd
authored
Jan 12, 2009
by
Raymond Hettinger
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Optimize heapq.nsmallest/nlargest for cases where n==1 or n>=size.
parent
c22ab18e
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Lib/heapq.py
Lib/heapq.py
+46
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Lib/heapq.py
View file @
b5bc33cd
...
@@ -129,7 +129,7 @@ From all times, sorting has always been a Great Art! :-)
...
@@ -129,7 +129,7 @@ From all times, sorting has always been a Great Art! :-)
__all__
=
[
'heappush'
,
'heappop'
,
'heapify'
,
'heapreplace'
,
'merge'
,
__all__
=
[
'heappush'
,
'heappop'
,
'heapify'
,
'heapreplace'
,
'merge'
,
'nlargest'
,
'nsmallest'
,
'heappushpop'
]
'nlargest'
,
'nsmallest'
,
'heappushpop'
]
from
itertools
import
islice
,
repeat
,
count
,
imap
,
izip
,
tee
from
itertools
import
islice
,
repeat
,
count
,
imap
,
izip
,
tee
,
chain
from
operator
import
itemgetter
,
neg
from
operator
import
itemgetter
,
neg
import
bisect
import
bisect
...
@@ -354,10 +354,32 @@ def nsmallest(n, iterable, key=None):
...
@@ -354,10 +354,32 @@ def nsmallest(n, iterable, key=None):
Equivalent to: sorted(iterable, key=key)[:n]
Equivalent to: sorted(iterable, key=key)[:n]
"""
"""
# Short-cut for n==1 is to use min() when len(iterable)>0
if
n
==
1
:
it
=
iter
(
iterable
)
head
=
list
(
islice
(
it
,
1
))
if
not
head
:
return
[]
if
key
is
None
:
return
[
min
(
chain
(
head
,
it
))]
return
[
min
(
chain
(
head
,
it
),
key
=
key
)]
# When n>=size, it's faster to use sort()
try
:
size
=
len
(
iterable
)
except
(
TypeError
,
AttributeError
):
pass
else
:
if
n
>=
size
:
return
sorted
(
iterable
,
key
=
key
)[:
n
]
# When key is none, use simpler decoration
if
key
is
None
:
if
key
is
None
:
it
=
izip
(
iterable
,
count
())
# decorate
it
=
izip
(
iterable
,
count
())
# decorate
result
=
_nsmallest
(
n
,
it
)
result
=
_nsmallest
(
n
,
it
)
return
map
(
itemgetter
(
0
),
result
)
# undecorate
return
map
(
itemgetter
(
0
),
result
)
# undecorate
# General case, slowest method
in1
,
in2
=
tee
(
iterable
)
in1
,
in2
=
tee
(
iterable
)
it
=
izip
(
imap
(
key
,
in1
),
count
(),
in2
)
# decorate
it
=
izip
(
imap
(
key
,
in1
),
count
(),
in2
)
# decorate
result
=
_nsmallest
(
n
,
it
)
result
=
_nsmallest
(
n
,
it
)
...
@@ -369,10 +391,33 @@ def nlargest(n, iterable, key=None):
...
@@ -369,10 +391,33 @@ def nlargest(n, iterable, key=None):
Equivalent to: sorted(iterable, key=key, reverse=True)[:n]
Equivalent to: sorted(iterable, key=key, reverse=True)[:n]
"""
"""
# Short-cut for n==1 is to use max() when len(iterable)>0
if
n
==
1
:
it
=
iter
(
iterable
)
head
=
list
(
islice
(
it
,
1
))
if
not
head
:
return
[]
if
key
is
None
:
return
[
max
(
chain
(
head
,
it
))]
return
[
max
(
chain
(
head
,
it
),
key
=
key
)]
# When n>=size, it's faster to use sort()
try
:
size
=
len
(
iterable
)
except
(
TypeError
,
AttributeError
):
pass
else
:
if
n
>=
size
:
return
sorted
(
iterable
,
key
=
key
,
reverse
=
True
)[:
n
]
# When key is none, use simpler decoration
if
key
is
None
:
if
key
is
None
:
it
=
izip
(
iterable
,
imap
(
neg
,
count
()))
# decorate
it
=
izip
(
iterable
,
imap
(
neg
,
count
()))
# decorate
result
=
_nlargest
(
n
,
it
)
result
=
_nlargest
(
n
,
it
)
return
map
(
itemgetter
(
0
),
result
)
# undecorate
return
map
(
itemgetter
(
0
),
result
)
# undecorate
# General case, slowest method
in1
,
in2
=
tee
(
iterable
)
in1
,
in2
=
tee
(
iterable
)
it
=
izip
(
imap
(
key
,
in1
),
imap
(
neg
,
count
()),
in2
)
# decorate
it
=
izip
(
imap
(
key
,
in1
),
imap
(
neg
,
count
()),
in2
)
# decorate
result
=
_nlargest
(
n
,
it
)
result
=
_nlargest
(
n
,
it
)
...
...
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