Skip to content
Projects
Groups
Snippets
Help
Loading...
Help
Support
Keyboard shortcuts
?
Submit feedback
Contribute to GitLab
Sign in / Register
Toggle navigation
C
cpython
Project overview
Project overview
Details
Activity
Releases
Repository
Repository
Files
Commits
Branches
Tags
Contributors
Graph
Compare
Issues
0
Issues
0
List
Boards
Labels
Milestones
Merge Requests
0
Merge Requests
0
Analytics
Analytics
Repository
Value Stream
Wiki
Wiki
Members
Members
Collapse sidebar
Close sidebar
Activity
Graph
Create a new issue
Commits
Issue Boards
Open sidebar
Kirill Smelkov
cpython
Commits
cd068129
Commit
cd068129
authored
Sep 18, 2009
by
Mark Dickinson
Browse files
Options
Browse Files
Download
Email Patches
Plain Diff
Issue #6713 (continued): remove unused arbitrary-base conversion code
from _PyLong_Format.
parent
81fd8040
Changes
1
Hide whitespace changes
Inline
Side-by-side
Showing
1 changed file
with
34 additions
and
99 deletions
+34
-99
Objects/longobject.c
Objects/longobject.c
+34
-99
No files found.
Objects/longobject.c
View file @
cd068129
...
...
@@ -1763,8 +1763,8 @@ long_to_decimal_string(PyObject *aa)
return
(
PyObject
*
)
str
;
}
/* Convert a long int object to a string, using a given conversion base
.
Return a string object.
/* Convert a long int object to a string, using a given conversion base
,
which should be one of 2, 8, 10 or 16.
Return a string object.
If base is 2, 8 or 16, add the proper prefix '0b', '0o' or '0x'. */
PyObject
*
...
...
@@ -1774,10 +1774,10 @@ _PyLong_Format(PyObject *aa, int base)
PyObject
*
str
;
Py_ssize_t
i
,
sz
;
Py_ssize_t
size_a
;
Py_UNICODE
*
p
;
Py_UNICODE
*
p
,
sign
=
'\0'
;
int
bits
;
char
sign
=
'\0'
;
assert
(
base
==
2
||
base
==
8
||
base
==
10
||
base
==
16
);
if
(
base
==
10
)
return
long_to_decimal_string
((
PyObject
*
)
a
);
...
...
@@ -1785,24 +1785,33 @@ _PyLong_Format(PyObject *aa, int base)
PyErr_BadInternalCall
();
return
NULL
;
}
assert
(
base
>=
2
&&
base
<=
36
);
size_a
=
ABS
(
Py_SIZE
(
a
));
/* Compute a rough upper bound for the length of the string */
i
=
base
;
bits
=
0
;
while
(
i
>
1
)
{
++
bits
;
i
>>=
1
;
}
i
=
5
;
/* ensure we don't get signed overflow in sz calculation */
if
(
size_a
>
(
PY_SSIZE_T_MAX
-
i
)
/
PyLong_SHIFT
)
{
switch
(
base
)
{
case
16
:
bits
=
4
;
break
;
case
8
:
bits
=
3
;
break
;
case
2
:
bits
=
1
;
break
;
default:
assert
(
0
);
/* shouldn't ever get here */
bits
=
0
;
/* to silence gcc warning */
}
/* compute length of output string: allow 2 characters for prefix and
1 for possible '-' sign. */
if
(
size_a
>
(
PY_SSIZE_T_MAX
-
3
)
/
PyLong_SHIFT
)
{
PyErr_SetString
(
PyExc_OverflowError
,
"int is too large to format"
);
return
NULL
;
}
sz
=
i
+
1
+
(
size_a
*
PyLong_SHIFT
-
1
)
/
bits
;
/* now size_a * PyLong_SHIFT + 3 <= PY_SSIZE_T_MAX, so the RHS below
is safe from overflow */
sz
=
3
+
(
size_a
*
PyLong_SHIFT
+
(
bits
-
1
))
/
bits
;
assert
(
sz
>=
0
);
str
=
PyUnicode_FromUnicode
(
NULL
,
sz
);
if
(
str
==
NULL
)
...
...
@@ -1815,106 +1824,32 @@ _PyLong_Format(PyObject *aa, int base)
if
(
Py_SIZE
(
a
)
==
0
)
{
*--
p
=
'0'
;
}
else
if
((
base
&
(
base
-
1
))
==
0
)
{
else
{
/* JRH: special case for power-of-2 bases */
twodigits
accum
=
0
;
int
accumbits
=
0
;
/* # of bits in accum */
int
basebits
=
1
;
/* # of bits in base-1 */
i
=
base
;
while
((
i
>>=
1
)
>
1
)
++
basebits
;
for
(
i
=
0
;
i
<
size_a
;
++
i
)
{
accum
|=
(
twodigits
)
a
->
ob_digit
[
i
]
<<
accumbits
;
accumbits
+=
PyLong_SHIFT
;
assert
(
accumbits
>=
b
aseb
its
);
assert
(
accumbits
>=
bits
);
do
{
char
cdigit
=
(
char
)(
accum
&
(
base
-
1
)
);
Py_UNICODE
cdigit
=
accum
&
(
base
-
1
);
cdigit
+=
(
cdigit
<
10
)
?
'0'
:
'a'
-
10
;
assert
(
p
>
PyUnicode_AS_UNICODE
(
str
));
*--
p
=
cdigit
;
accumbits
-=
basebits
;
accum
>>=
basebits
;
}
while
(
i
<
size_a
-
1
?
accumbits
>=
basebits
:
accum
>
0
);
}
}
else
{
/* Not 0, and base not a power of 2. Divide repeatedly by
base, but for speed use the highest power of base that
fits in a digit. */
Py_ssize_t
size
=
size_a
;
digit
*
pin
=
a
->
ob_digit
;
PyLongObject
*
scratch
;
/* powbasw <- largest power of base that fits in a digit. */
digit
powbase
=
base
;
/* powbase == base ** power */
int
power
=
1
;
for
(;;)
{
twodigits
newpow
=
powbase
*
(
twodigits
)
base
;
if
(
newpow
>>
PyLong_SHIFT
)
/* doesn't fit in a digit */
break
;
powbase
=
(
digit
)
newpow
;
++
power
;
}
/* Get a scratch area for repeated division. */
scratch
=
_PyLong_New
(
size
);
if
(
scratch
==
NULL
)
{
Py_DECREF
(
str
);
return
NULL
;
accumbits
-=
bits
;
accum
>>=
bits
;
}
while
(
i
<
size_a
-
1
?
accumbits
>=
bits
:
accum
>
0
);
}
/* Repeatedly divide by powbase. */
do
{
int
ntostore
=
power
;
digit
rem
=
inplace_divrem1
(
scratch
->
ob_digit
,
pin
,
size
,
powbase
);
pin
=
scratch
->
ob_digit
;
/* no need to use a again */
if
(
pin
[
size
-
1
]
==
0
)
--
size
;
SIGCHECK
({
Py_DECREF
(
scratch
);
Py_DECREF
(
str
);
return
NULL
;
})
/* Break rem into digits. */
assert
(
ntostore
>
0
);
do
{
digit
nextrem
=
(
digit
)(
rem
/
base
);
char
c
=
(
char
)(
rem
-
nextrem
*
base
);
assert
(
p
>
PyUnicode_AS_UNICODE
(
str
));
c
+=
(
c
<
10
)
?
'0'
:
'a'
-
10
;
*--
p
=
c
;
rem
=
nextrem
;
--
ntostore
;
/* Termination is a bit delicate: must not
store leading zeroes, so must get out if
remaining quotient and rem are both 0. */
}
while
(
ntostore
&&
(
size
||
rem
));
}
while
(
size
!=
0
);
Py_DECREF
(
scratch
);
}
if
(
base
==
16
)
{
if
(
base
==
16
)
*--
p
=
'x'
;
*--
p
=
'0'
;
}
else
if
(
base
==
8
)
{
else
if
(
base
==
8
)
*--
p
=
'o'
;
*--
p
=
'0'
;
}
else
if
(
base
==
2
)
{
else
/* (base == 2) */
*--
p
=
'b'
;
*--
p
=
'0'
;
}
else
if
(
base
!=
10
)
{
*--
p
=
'#'
;
*--
p
=
'0'
+
base
%
10
;
if
(
base
>
10
)
*--
p
=
'0'
+
base
/
10
;
}
*--
p
=
'0'
;
if
(
sign
)
*--
p
=
sign
;
if
(
p
!=
PyUnicode_AS_UNICODE
(
str
))
{
...
...
Write
Preview
Markdown
is supported
0%
Try again
or
attach a new file
Attach a file
Cancel
You are about to add
0
people
to the discussion. Proceed with caution.
Finish editing this message first!
Cancel
Please
register
or
sign in
to comment