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Kirill Smelkov
cpython
Commits
d04fa31f
Commit
d04fa31f
authored
16 years ago
by
Raymond Hettinger
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Minor doc fixes.
parent
1c62dc9d
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4
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11 additions
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8 deletions
+11
-8
Doc/glossary.rst
Doc/glossary.rst
+1
-1
Doc/library/collections.rst
Doc/library/collections.rst
+1
-1
Doc/library/itertools.rst
Doc/library/itertools.rst
+3
-3
Lib/test/test_itertools.py
Lib/test/test_itertools.py
+6
-3
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Doc/glossary.rst
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d04fa31f
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@@ -393,7 +393,7 @@ Glossary
also :term:`immutable`.
named tuple
Any tuple
sub
class whose indexable elements are also accessible using
Any tuple
-like
class whose indexable elements are also accessible using
named attributes (for example, :func:`time.localtime` returns a
tuple-like object where the *year* is accessible either with an
index such as ``t[0]`` or with a named attribute like ``t.tm_year``).
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Doc/library/collections.rst
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d04fa31f
...
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@@ -206,7 +206,7 @@ For example::
.. method:: most_common([n])
Return a list of the *n* most common elements and their counts from the
most common to the least. If *n* not specified, :func:`most_common`
most common to the least. If *n*
is
not specified, :func:`most_common`
returns *all* elements in the counter. Elements with equal counts are
ordered arbitrarily::
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Doc/library/itertools.rst
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d04fa31f
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@@ -290,7 +290,7 @@ loops that truncate the stream.
class groupby(object):
# [k for k, g in groupby('AAAABBBCCDAABBB')] --> A B C D A B
# [
(list(g)
) for k, g in groupby('AAAABBBCCD')] --> AAAA BBB CC D
# [
list(g
) for k, g in groupby('AAAABBBCCD')] --> AAAA BBB CC D
def __init__(self, iterable, key=None):
if key is None:
key = lambda x: x
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@@ -591,8 +591,8 @@ which incur interpreter overhead.
return map(function, count(start))
def nth(iterable, n):
"Returns the nth item or
empty list
"
return
list(islice(iterable, n, n+1)
)
"Returns the nth item or
None
"
return
next(islice(iterable, n, None), None
)
def quantify(iterable, pred=bool):
"Count how many times the predicate is true"
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Lib/test/test_itertools.py
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d04fa31f
...
...
@@ -1371,8 +1371,8 @@ Samuele
... return map(function, count(start))
>>> def nth(iterable, n):
... "Returns the nth item or
empty list
"
... return
list(islice(iterable, n, n+1)
)
... "Returns the nth item or
None
"
... return
next(islice(iterable, n, None), None
)
>>> def quantify(iterable, pred=bool):
... "Count how many times the predicate is true"
...
...
@@ -1469,7 +1469,10 @@ perform as purported.
[0, 2, 4, 6]
>>> nth('abcde', 3)
['d']
'd'
>>> nth('abcde', 9) is None
True
>>> quantify(range(99), lambda x: x%2==0)
50
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