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Kirill Smelkov
cpython
Commits
d391d10d
Commit
d391d10d
authored
Jun 07, 2005
by
Raymond Hettinger
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Add a decimal FAQ
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7e87a8a0
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Doc/lib/libdecimal.tex
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Doc/lib/libdecimal.tex
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d391d10d
...
...
@@ -525,11 +525,11 @@ The \class{Context} class defines several general purpose methods as well as a
large number of methods for doing arithmetic directly in a given context.
\begin{methoddesc}
{
clear
_
flags
}{}
S
ets all of the flags to
\constant
{
0
}
.
Res
ets all of the flags to
\constant
{
0
}
.
\end{methoddesc}
\begin{methoddesc}
{
copy
}{}
Return
s
a duplicate of the context.
Return a duplicate of the context.
\end{methoddesc}
\begin{methoddesc}
{
create
_
decimal
}{
num
}
...
...
@@ -1118,3 +1118,156 @@ def sin(x):
return +s
\end{verbatim}
\subsection
{
Decimal FAQ
\label
{
decimal-faq
}}
Q. It is cumbersome to type
\code
{
decimal.Decimal('1234.5')
}
. Is there a way
to minimize typing when using the interactive interpreter?
A. Some users abbreviate the constructor to just a single letter:
\begin{verbatim}
>>> D = decimal.Decimal
>>> D('1.23') + D('3.45')
Decimal("4.68")
\end{verbatim}
Q. In a fixed-point application to two decimal places, some inputs
have many places and need to be rounded. Others are not supposed to have
excess digits and need to be validated. What methods should be used?
A. The
\method
{
quantize()
}
method rounds to a fixed number of decimal places.
If the
\constant
{
Inexact
}
trap is set, it is also useful for validation:
\begin{verbatim}
>>> TWOPLACES = Decimal(10) ** -2 # same as Decimal('0.01')
>>> # Round to two places
>>> Decimal("3.214").quantize(TWOPLACES)
Decimal("3.21")
>>> # Validate that a number does not exceed two places
>>> Decimal("3.21").quantize(TWOPLACES, context=Context(traps=[Inexact]))
Decimal("3.21")
>>> Decimal("3.214").quantize(TWOPLACES, context=Context(traps=[Inexact]))
Traceback (most recent call last):
...
Inexact: Changed in rounding
\end{verbatim}
Q. Once I have valid two place inputs, how do I maintain that invariant
throughout an application?
A. Some operations like addition and subtraction automatically preserve fixed
point. Others, like multiplication and division, change the number of decimal
places and need to be followed-up with a
\method
{
quantize()
}
step.
Q. There are many ways to write express the same value. The numbers
\constant
{
200
}
,
\constant
{
200.000
}
,
\constant
{
2E2
}
, and
\constant
{
.02E+4
}
all
have the same value at various precisions. Is there a way to transform them to
a single recognizable canonical value?
A. The
\method
{
normalize()
}
method maps all equivalent values to a single
representive:
\begin{verbatim}
>>> values = map(Decimal, '200 200.000 2E2 .02E+4'.split())
>>> [v.normalize() for v in values]
[Decimal("2E+2"), Decimal("2E+2"), Decimal("2E+2"), Decimal("2E+2")]
\end{verbatim}
Q. Is there a way to convert a regular float to a
\class
{
Decimal
}
?
A. Yes, all binary floating point numbers can be exactly expressed as a
Decimal. An exact conversion may take more precision than intuition would
suggest, so trapping
\constant
{
Inexact
}
will signal a need for more precision:
\begin{verbatim}
def floatToDecimal(f):
"Convert a floating point number to a Decimal with no loss of information"
# Transform (exactly) a float to a mantissa (0.5 <= abs(m) < 1.0) and an
# exponent. Double the mantissa until it is an integer. Use the integer
# mantissa and exponent to compute an equivalent Decimal. If this cannot
# be done exactly, then retry with more precision.
mantissa, exponent = math.frexp(f)
while mantissa != int(mantissa):
mantissa *= 2.0
exponent -= 1
mantissa = int(mantissa)
oldcontext = getcontext()
setcontext(Context(traps=[Inexact]))
try:
while True:
try:
return mantissa * Decimal(2) ** exponent
except Inexact:
getcontext().prec += 1
finally:
setcontext(oldcontext)
\end{verbatim}
Q. Why isn't the
\function
{
floatToDecimal()
}
routine included in the module?
A. There is some question about whether it is advisable to mix binary and
decimal floating point. Also, its use requires some care to avoid the
representation issues associated with binary floating point:
\begin{verbatim}
>>> floatToDecimal(1.1)
Decimal("1.100000000000000088817841970012523233890533447265625")
\end{verbatim}
Q. Within a complex calculation, how can I make sure that I haven't gotten a
spurious result because of insufficient precision or rounding anomalies.
A. The decimal module makes it easy to test results. A best practice is to
re-run calculations using greater precision and with various rounding modes.
Widely differing results indicate insufficient precision, rounding mode
issues, ill-conditioned inputs, or a numerically unstable algorithm.
Q. I noticed that context precision is applied to the results of operations
but not to the inputs. Is there anything to watch out for when mixing
values of different precisions?
A. Yes. The principle is that all values are considered to be exact and so
is the arithmetic on those values. Only the results are rounded. The
advantage for inputs is that ``what you type is what you get''. A
disadvantage is that the results can look odd if you forget that the inputs
haven't been rounded:
\begin{verbatim}
>>> getcontext().prec = 3
>>> Decimal('3.104') + D('2.104')
Decimal("5.21")
>>> Decimal('3.104') + D('0.000') + D('2.104')
Decimal("5.20")
\end{verbatim}
The solution is either to increase precision or to force rounding of inputs
using the unary plus operation:
\begin{verbatim}
>>> getcontext().prec = 3
>>> +Decimal('1.23456789') # unary plus triggers rounding
Decimal("1.23")
\end{verbatim}
Alternatively, inputs can be rounded upon creation using the
\method
{
Context.create
_
decimal()
}
method:
\begin{verbatim}
>>> Context(prec=5, rounding=ROUND
_
DOWN).create
_
decimal('1.2345678')
Decimal("1.2345")
\end{verbatim}
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