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Kirill Smelkov
cpython
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d44af82e
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d44af82e
authored
Nov 12, 2011
by
Eli Bendersky
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Issue #12767: documenting threading.Condition.notify
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Doc/library/threading.rst
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@@ -634,20 +634,21 @@ the call as often as necessary.
.. versionadded:: 3.2
.. method:: notify()
.. method:: notify(
n=1
)
Wake up a thread waiting on this condition, if any. If the calling thread
has not acquired the lock when this method is called, a
By default, wake up one thread waiting on this condition, if any. If the
calling thread
has not acquired the lock when this method is called, a
:exc:`RuntimeError` is raised.
This method wakes up
one
of the threads waiting for the condition
variable
, if any are waiting
; it is a no-op if no threads are waiting.
This method wakes up
at most *n*
of the threads waiting for the condition
variable; it is a no-op if no threads are waiting.
The current implementation wakes up exactly one thread, if any are
waiting. However, it's not safe to rely on this behavior. A future,
optimized implementation may occasionally wake up more than one thread.
The current implementation wakes up exactly *n* threads, if at least *n*
threads are waiting. However, it's not safe to rely on this behavior.
A future, optimized implementation may occasionally wake up more than
*n* threads.
Note:
the
awakened thread does not actually return from its :meth:`wait`
Note:
an
awakened thread does not actually return from its :meth:`wait`
call until it can reacquire the lock. Since :meth:`notify` does not
release the lock, its caller should.
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