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Kirill Smelkov
cpython
Commits
e9af284e
Commit
e9af284e
authored
Aug 17, 2007
by
Georg Brandl
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No need to define raw_input(), input() does the same.
parent
ed44a1a6
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21 deletions
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-21
Doc/tutorial/controlflow.rst
Doc/tutorial/controlflow.rst
+2
-14
Doc/tutorial/errors.rst
Doc/tutorial/errors.rst
+1
-7
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Doc/tutorial/controlflow.rst
View file @
e9af284e
...
...
@@ -16,13 +16,7 @@ control flow statements known from other languages, with some twists.
Perhaps the most well-known statement type is the :keyword:`if` statement. For
example::
>>> def raw_input(prompt):
... import sys
... sys.stdout.write(prompt)
... sys.stdout.flush()
... return sys.stdin.readline()
...
>>> x = int(raw_input("Please enter an integer: "))
>>> x = int(input("Please enter an integer: "))
>>> if x < 0:
... x = 0
... print 'Negative changed to zero'
...
...
@@ -298,15 +292,9 @@ The most useful form is to specify a default value for one or more arguments.
This creates a function that can be called with fewer arguments than it is
defined to allow. For example::
def raw_input(prompt):
import sys
sys.stdout.write(prompt)
sys.stdout.flush()
return sys.stdin.readline()
def ask_ok(prompt, retries=4, complaint='Yes or no, please!'):
while True:
ok =
raw_
input(prompt)
ok = input(prompt)
if ok in ('y', 'ye', 'yes'): return True
if ok in ('n', 'no', 'nop', 'nope'): return False
retries = retries - 1
...
...
Doc/tutorial/errors.rst
View file @
e9af284e
...
...
@@ -85,15 +85,9 @@ entered, but allows the user to interrupt the program (using :kbd:`Control-C` or
whatever the operating system supports); note that a user-generated interruption
is signalled by raising the :exc:`KeyboardInterrupt` exception. ::
>>> def raw_input(prompt):
... import sys
... sys.stdout.write(prompt)
... sys.stdout.flush()
... return sys.stdin.readline()
...
>>> while True:
... try:
... x = int(
raw_
input("Please enter a number: "))
... x = int(input("Please enter a number: "))
... break
... except ValueError:
... print "Oops! That was no valid number. Try again..."
...
...
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