Free the recently allocated qcam in each case.

The semantic match that finds this problem is as follows:

// <smpl>
@r@
identifier x;
@@

kfree(x)

@@
identifier r.x;
expression E1!=0,E2,E3,E4;
statement S;
@@

(
if (<+...x...+>) S
|
if (...) { ... when != kfree(x)
               when != if (...) { ... kfree(x); ... }
               when != x = E3
* return E1;
}
... when != x = E2
if (...) { ... when != x = E4
 kfree(x); ... return ...; }
)
// </smpl>
Signed-off-by: Julia Lawall <julia@diku.dk>
Signed-off-by: Mauro Carvalho Chehab <mchehab@redhat.com>