ASoC: nau8821: Don't unconditionally free interrupt

The remove() operation unconditionally frees the interrupt for the device
but we may not actually have an interrupt so there might be nothing to
free. Since the interrupt is requested after all other resources we don't
need the explicit free anyway, unwinding is guaranteed to be safe, so just
delete the remove() function and let devm take care of things.
Reported-by: Zheyu Ma <zheyuma97@gmail.com>
Signed-off-by: Mark Brown <broonie@kernel.org>
Tested-by: Zheyu Ma <zheyuma97@gmail.com>
Link: https://lore.kernel.org/r/20220718140405.57233-1-broonie@kernel.orgSigned-off-by: Mark Brown <broonie@kernel.org>

sound/soc/codecs/nau8821.c

@@ -1729,15 +1729,6 @@ static int nau8821_i2c_probe(struct i2c_client *i2c)
 	return ret;
 }
 
-static int nau8821_i2c_remove(struct i2c_client *i2c_client)
-{
-	struct nau8821 *nau8821 = i2c_get_clientdata(i2c_client);
-
-	devm_free_irq(nau8821->dev, nau8821->irq, nau8821);
-
-	return 0;
-}
-
 static const struct i2c_device_id nau8821_i2c_ids[] = {
 	{ "nau8821", 0 },
 	{ }
@@ -1767,7 +1758,6 @@ static struct i2c_driver nau8821_driver = {
 		.acpi_match_table = ACPI_PTR(nau8821_acpi_match),
 	},
 	.probe_new = nau8821_i2c_probe,
-	.remove = nau8821_i2c_remove,
 	.id_table = nau8821_i2c_ids,
 };
 module_i2c_driver(nau8821_driver);