pinctrl: rzn1: Add of_node_put() before return

Each iteration of for_each_child_of_node puts the previous node, but in
the case of a return from the middle of the loop, there is no put, thus
causing a memory leak. Hence add an of_node_put before the return in
three places.
Issue found with Coccinelle.
Signed-off-by: Nishka Dasgupta <nishkadg.linux@gmail.com>
Signed-off-by: Geert Uytterhoeven <geert+renesas@glider.be>

drivers/pinctrl/pinctrl-rzn1.c

@@ -412,8 +412,10 @@ static int rzn1_dt_node_to_map(struct pinctrl_dev *pctldev,
 
 	for_each_child_of_node(np, child) {
 		ret = rzn1_dt_node_to_map_one(pctldev, child, map, num_maps);
-		if (ret < 0)
+		if (ret < 0) {
+			of_node_put(child);
 			return ret;
+		}
 	}
 
 	return 0;
@@ -792,8 +794,10 @@ static int rzn1_pinctrl_parse_functions(struct device_node *np,
 		grp = &ipctl->groups[ipctl->ngroups];
 		grp->func = func->name;
 		ret = rzn1_pinctrl_parse_groups(child, grp, ipctl);
-		if (ret < 0)
+		if (ret < 0) {
+			of_node_put(child);
 			return ret;
+		}
 		i++;
 		ipctl->ngroups++;
 	}
@@ -838,8 +842,10 @@ static int rzn1_pinctrl_probe_dt(struct platform_device *pdev,
 
 	for_each_child_of_node(np, child) {
 		ret = rzn1_pinctrl_parse_functions(child, ipctl, i++);
-		if (ret < 0)
+		if (ret < 0) {
+			of_node_put(child);
 			return ret;
+		}
 	}
 
 	return 0;