slub: Prepare __slab_free() for unfrozen partial slab out of node partial list
Now the partially empty slub will be frozen when taken out of node partial list, so the __slab_free() will know from "was_frozen" that the partially empty slab is not on node partial list and is a cpu or cpu partial slab of some cpu. But we will change this, make partial slabs leave the node partial list with unfrozen state, so we need to change __slab_free() to use the new slab_test_node_partial() we just introduced. Signed-off-by: Chengming Zhou <zhouchengming@bytedance.com> Reviewed-by: Vlastimil Babka <vbabka@suse.cz> Tested-by: Hyeonggon Yoo <42.hyeyoo@gmail.com> Reviewed-by: Hyeonggon Yoo <42.hyeyoo@gmail.com> Signed-off-by: Vlastimil Babka <vbabka@suse.cz>
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