mfd: 88pm80x: Double shifting bug in suspend/resume

BugLink: http://bugs.launchpad.net/bugs/1634153

commit 9a6dc644 upstream.

set_bit() and clear_bit() take the bit number so this code is really
doing "1 << (1 << irq)" which is a double shift bug.  It's done
consistently so it won't cause a problem unless "irq" is more than 4.

Fixes: 70c6cce0 ('mfd: Support 88pm80x in 80x driver')
Signed-off-by: Dan Carpenter <dan.carpenter@oracle.com>
Signed-off-by: Lee Jones <lee.jones@linaro.org>
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
Signed-off-by: Tim Gardner <tim.gardner@canonical.com>
Signed-off-by: Seth Forshee <seth.forshee@canonical.com>

include/linux/mfd/88pm80x.h

@@ -350,7 +350,7 @@ static inline int pm80x_dev_suspend(struct device *dev)
 	int irq = platform_get_irq(pdev, 0);
 
 	if (device_may_wakeup(dev))
-		set_bit((1 << irq), &chip->wu_flag);
+		set_bit(irq, &chip->wu_flag);
 
 	return 0;
 }
@@ -362,7 +362,7 @@ static inline int pm80x_dev_resume(struct device *dev)
 	int irq = platform_get_irq(pdev, 0);
 
 	if (device_may_wakeup(dev))
-		clear_bit((1 << irq), &chip->wu_flag);
+		clear_bit(irq, &chip->wu_flag);
 
 	return 0;
 }