Commit 5872331b authored by Eric Sandeen's avatar Eric Sandeen Committed by Theodore Ts'o

ext4: fix potential negative array index in do_split()

If for any reason a directory passed to do_split() does not have enough
active entries to exceed half the size of the block, we can end up
iterating over all "count" entries without finding a split point.

In this case, count == move, and split will be zero, and we will
attempt a negative index into map[].

Guard against this by detecting this case, and falling back to
split-to-half-of-count instead; in this case we will still have
plenty of space (> half blocksize) in each split block.

Fixes: ef2b02d3 ("ext34: ensure do_split leaves enough free space in both blocks")
Signed-off-by: default avatarEric Sandeen <sandeen@redhat.com>
Reviewed-by: default avatarAndreas Dilger <adilger@dilger.ca>
Reviewed-by: default avatarJan Kara <jack@suse.cz>
Link: https://lore.kernel.org/r/f53e246b-647c-64bb-16ec-135383c70ad7@redhat.comSigned-off-by: default avatarTheodore Ts'o <tytso@mit.edu>
parent 24dc9864
...@@ -1858,7 +1858,7 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir, ...@@ -1858,7 +1858,7 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir,
blocksize, hinfo, map); blocksize, hinfo, map);
map -= count; map -= count;
dx_sort_map(map, count); dx_sort_map(map, count);
/* Split the existing block in the middle, size-wise */ /* Ensure that neither split block is over half full */
size = 0; size = 0;
move = 0; move = 0;
for (i = count-1; i >= 0; i--) { for (i = count-1; i >= 0; i--) {
...@@ -1868,8 +1868,18 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir, ...@@ -1868,8 +1868,18 @@ static struct ext4_dir_entry_2 *do_split(handle_t *handle, struct inode *dir,
size += map[i].size; size += map[i].size;
move++; move++;
} }
/* map index at which we will split */ /*
split = count - move; * map index at which we will split
*
* If the sum of active entries didn't exceed half the block size, just
* split it in half by count; each resulting block will have at least
* half the space free.
*/
if (i > 0)
split = count - move;
else
split = count/2;
hash2 = map[split].hash; hash2 = map[split].hash;
continued = hash2 == map[split - 1].hash; continued = hash2 == map[split - 1].hash;
dxtrace(printk(KERN_INFO "Split block %lu at %x, %i/%i\n", dxtrace(printk(KERN_INFO "Split block %lu at %x, %i/%i\n",
......
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment