Commit 731b918a authored by Jacob Keller's avatar Jacob Keller Committed by Greg Kroah-Hartman

i40e: free the skb after clearing the bitlock

[ Upstream commit c79756cb ]

In commit bbc4e7d2 ("i40e: fix race condition with PTP_TX_IN_PROGRESS
bits") we modified the code which handles Tx timestamps so that we would
clear the progress bit as soon as possible.

A later commit 0bc0706b ("i40e: check for Tx timestamp timeouts during
watchdog") introduced similar code for detecting and handling cleanup of
a blocked Tx timestamp. This code did not use the same pattern for cleaning
up the skb.

Update this code to wait to free the skb until after the bit lock is
free, by first setting the ptp_tx_skb to NULL and clearing the lock.
Signed-off-by: default avatarJacob Keller <jacob.e.keller@intel.com>
Tested-by: default avatarAndrew Bowers <andrewx.bowers@intel.com>
Signed-off-by: default avatarJeff Kirsher <jeffrey.t.kirsher@intel.com>
Signed-off-by: default avatarSasha Levin <alexander.levin@microsoft.com>
Signed-off-by: default avatarGreg Kroah-Hartman <gregkh@linuxfoundation.org>
parent 6fdc5235
......@@ -337,6 +337,8 @@ void i40e_ptp_rx_hang(struct i40e_pf *pf)
**/
void i40e_ptp_tx_hang(struct i40e_pf *pf)
{
struct sk_buff *skb;
if (!(pf->flags & I40E_FLAG_PTP) || !pf->ptp_tx)
return;
......@@ -349,9 +351,12 @@ void i40e_ptp_tx_hang(struct i40e_pf *pf)
* within a second it is reasonable to assume that we never will.
*/
if (time_is_before_jiffies(pf->ptp_tx_start + HZ)) {
dev_kfree_skb_any(pf->ptp_tx_skb);
skb = pf->ptp_tx_skb;
pf->ptp_tx_skb = NULL;
clear_bit_unlock(__I40E_PTP_TX_IN_PROGRESS, pf->state);
/* Free the skb after we clear the bitlock */
dev_kfree_skb_any(skb);
pf->tx_hwtstamp_timeouts++;
}
}
......
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment