Commit 77a92660 authored by Masahiro Yamada's avatar Masahiro Yamada

kconfig: remove wrong expr_trans_bool()

expr_trans_bool() performs an incorrect transformation.

[Test Code]

    config MODULES
            def_bool y
            modules

    config A
            def_bool y
            select C if B != n

    config B
            def_tristate m

    config C
            tristate

[Result]

    CONFIG_MODULES=y
    CONFIG_A=y
    CONFIG_B=m
    CONFIG_C=m

This output is incorrect because CONFIG_C=y is expected.

Documentation/kbuild/kconfig-language.rst clearly explains the function
of the '!=' operator:

    If the values of both symbols are equal, it returns 'n',
    otherwise 'y'.

Therefore, the statement:

    select C if B != n

should be equivalent to:

    select C if y

Or, more simply:

    select C

Hence, the symbol C should be selected by the value of A, which is 'y'.

However, expr_trans_bool() wrongly transforms it to:

    select C if B

Therefore, the symbol C is selected by (A && B), which is 'm'.

The comment block of expr_trans_bool() correctly explains its intention:

  * bool FOO!=n => FOO
    ^^^^

If FOO is bool, FOO!=n can be simplified into FOO. This is correct.

However, the actual code performs this transformation when FOO is
tristate:

    if (e->left.sym->type == S_TRISTATE) {
                             ^^^^^^^^^^

While it can be fixed to S_BOOLEAN, there is no point in doing so
because expr_tranform() already transforms FOO!=n to FOO when FOO is
bool. (see the "case E_UNEQUAL" part)

expr_trans_bool() is wrong and unnecessary.
Signed-off-by: default avatarMasahiro Yamada <masahiroy@kernel.org>
Acked-by: default avatarRandy Dunlap <rdunlap@infradead.org>
parent 45c7f555
......@@ -396,35 +396,6 @@ static struct expr *expr_eliminate_yn(struct expr *e)
return e;
}
/*
* bool FOO!=n => FOO
*/
struct expr *expr_trans_bool(struct expr *e)
{
if (!e)
return NULL;
switch (e->type) {
case E_AND:
case E_OR:
case E_NOT:
e->left.expr = expr_trans_bool(e->left.expr);
e->right.expr = expr_trans_bool(e->right.expr);
break;
case E_UNEQUAL:
// FOO!=n -> FOO
if (e->left.sym->type == S_TRISTATE) {
if (e->right.sym == &symbol_no) {
e->type = E_SYMBOL;
e->right.sym = NULL;
}
}
break;
default:
;
}
return e;
}
/*
* e1 || e2 -> ?
*/
......
......@@ -284,7 +284,6 @@ void expr_free(struct expr *e);
void expr_eliminate_eq(struct expr **ep1, struct expr **ep2);
int expr_eq(struct expr *e1, struct expr *e2);
tristate expr_calc_value(struct expr *e);
struct expr *expr_trans_bool(struct expr *e);
struct expr *expr_eliminate_dups(struct expr *e);
struct expr *expr_transform(struct expr *e);
int expr_contains_symbol(struct expr *dep, struct symbol *sym);
......
......@@ -398,8 +398,6 @@ static void _menu_finalize(struct menu *parent, bool inside_choice)
dep = expr_transform(dep);
dep = expr_alloc_and(expr_copy(basedep), dep);
dep = expr_eliminate_dups(dep);
if (menu->sym && menu->sym->type != S_TRISTATE)
dep = expr_trans_bool(dep);
prop->visible.expr = dep;
/*
......
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment