btrfs: export comp_keys() from ctree.c as btrfs_comp_keys()

Export comp_keys() out of ctree.c, as btrfs_comp_keys(), so that in a
later patch we can move out defrag specific code from ctree.c into
defrag.c.
Signed-off-by: Filipe Manana <fdmanana@suse.com>
Reviewed-by: David Sterba <dsterba@suse.com>
Signed-off-by: David Sterba <dsterba@suse.com>

fs/btrfs/ctree.c

@@ -749,36 +749,6 @@ static int close_blocks(u64 blocknr, u64 other, u32 blocksize)
 	return 0;
 }
 
-#ifdef __LITTLE_ENDIAN
-
-/*
- * Compare two keys, on little-endian the disk order is same as CPU order and
- * we can avoid the conversion.
- */
-static int comp_keys(const struct btrfs_disk_key *disk_key,
-		     const struct btrfs_key *k2)
-{
-	const struct btrfs_key *k1 = (const struct btrfs_key *)disk_key;
-
-	return btrfs_comp_cpu_keys(k1, k2);
-}
-
-#else
-
-/*
- * compare two keys in a memcmp fashion
- */
-static int comp_keys(const struct btrfs_disk_key *disk,
-		     const struct btrfs_key *k2)
-{
-	struct btrfs_key k1;
-
-	btrfs_disk_key_to_cpu(&k1, disk);
-
-	return btrfs_comp_cpu_keys(&k1, k2);
-}
-#endif
-
 /*
  * same as comp_keys only with two btrfs_key's
  */
@@ -851,7 +821,7 @@ int btrfs_realloc_node(struct btrfs_trans_handle *trans,
 		int close = 1;
 
 		btrfs_node_key(parent, &disk_key, i);
-		if (!progress_passed && comp_keys(&disk_key, progress) < 0)
+		if (!progress_passed && btrfs_comp_keys(&disk_key, progress) < 0)
 			continue;
 
 		progress_passed = 1;
@@ -964,7 +934,7 @@ int btrfs_bin_search(struct extent_buffer *eb, int first_slot,
 			tmp = &unaligned;
 		}
 
-		ret = comp_keys(tmp, key);
+		ret = btrfs_comp_keys(tmp, key);
 
 		if (ret < 0)
 			low = mid + 1;
@@ -2001,7 +1971,7 @@ static int search_leaf(struct btrfs_trans_handle *trans,
 			 * the extent buffer's header and we have recently accessed
 			 * the header's level field.
 			 */
-			ret = comp_keys(&first_key, key);
+			ret = btrfs_comp_keys(&first_key, key);
 			if (ret < 0) {
 				/*
 				 * The first key is smaller than the key we want
@@ -2510,7 +2480,7 @@ static int btrfs_prev_leaf(struct btrfs_root *root, struct btrfs_path *path)
 	 */
 	if (path->slots[0] < btrfs_header_nritems(path->nodes[0])) {
 		btrfs_item_key(path->nodes[0], &found_key, path->slots[0]);
-		ret = comp_keys(&found_key, &orig_key);
+		ret = btrfs_comp_keys(&found_key, &orig_key);
 		if (ret == 0) {
 			if (path->slots[0] > 0) {
 				path->slots[0]--;
@@ -2525,7 +2495,7 @@ static int btrfs_prev_leaf(struct btrfs_root *root, struct btrfs_path *path)
 	}
 
 	btrfs_item_key(path->nodes[0], &found_key, 0);
-	ret = comp_keys(&found_key, &key);
+	ret = btrfs_comp_keys(&found_key, &key);
 	/*
 	 * We might have had an item with the previous key in the tree right
 	 * before we released our path. And after we released our path, that
@@ -2716,7 +2686,7 @@ void btrfs_set_item_key_safe(struct btrfs_trans_handle *trans,
 	slot = path->slots[0];
 	if (slot > 0) {
 		btrfs_item_key(eb, &disk_key, slot - 1);
-		if (unlikely(comp_keys(&disk_key, new_key) >= 0)) {
+		if (unlikely(btrfs_comp_keys(&disk_key, new_key) >= 0)) {
 			btrfs_print_leaf(eb);
 			btrfs_crit(fs_info,
 		"slot %u key (%llu %u %llu) new key (%llu %u %llu)",
@@ -2730,7 +2700,7 @@ void btrfs_set_item_key_safe(struct btrfs_trans_handle *trans,
 	}
 	if (slot < btrfs_header_nritems(eb) - 1) {
 		btrfs_item_key(eb, &disk_key, slot + 1);
-		if (unlikely(comp_keys(&disk_key, new_key) <= 0)) {
+		if (unlikely(btrfs_comp_keys(&disk_key, new_key) <= 0)) {
 			btrfs_print_leaf(eb);
 			btrfs_crit(fs_info,
 		"slot %u key (%llu %u %llu) new key (%llu %u %llu)",

fs/btrfs/ctree.h

@@ -9,6 +9,7 @@
 #include <linux/pagemap.h>
 #include "locking.h"
 #include "fs.h"
+#include "accessors.h"
 
 struct btrfs_trans_handle;
 struct btrfs_transaction;
@@ -464,6 +465,36 @@ int btrfs_bin_search(struct extent_buffer *eb, int first_slot,
 		     const struct btrfs_key *key, int *slot);
 
 int __pure btrfs_comp_cpu_keys(const struct btrfs_key *k1, const struct btrfs_key *k2);
+
+#ifdef __LITTLE_ENDIAN
+
+/*
+ * Compare two keys, on little-endian the disk order is same as CPU order and
+ * we can avoid the conversion.
+ */
+static inline int btrfs_comp_keys(const struct btrfs_disk_key *disk_key,
+				  const struct btrfs_key *k2)
+{
+	const struct btrfs_key *k1 = (const struct btrfs_key *)disk_key;
+
+	return btrfs_comp_cpu_keys(k1, k2);
+}
+
+#else
+
+/* Compare two keys in a memcmp fashion. */
+static inline int btrfs_comp_keys(const struct btrfs_disk_key *disk,
+				  const struct btrfs_key *k2)
+{
+	struct btrfs_key k1;
+
+	btrfs_disk_key_to_cpu(&k1, disk);
+
+	return btrfs_comp_cpu_keys(&k1, k2);
+}
+
+#endif
+
 int btrfs_previous_item(struct btrfs_root *root,
 			struct btrfs_path *path, u64 min_objectid,
 			int type);