Commit d9194e00 authored by Frank Rowand's avatar Frank Rowand Committed by Rob Herring

of: dynamic: add lifecycle docbook info to node creation functions

The existing docbook comments for the functions related to creating
a devicetree node do not explain the reference count of a newly
created node, how decrementing the reference count to zero will
free the associated memory, and the caller's responsibility to
call of_node_put() on the node.  Explain what happens when the
reference count is decremented to zero.
Signed-off-by: default avatarFrank Rowand <frowand.list@gmail.com>
Link: https://lore.kernel.org/r/20230213185702.395776-8-frowand.list@gmail.comSigned-off-by: default avatarRob Herring <robh@kernel.org>
parent ec0b7e24
......@@ -443,7 +443,8 @@ struct property *__of_prop_dup(const struct property *prop, gfp_t allocflags)
* another node. The node data are dynamically allocated and all the node
* flags have the OF_DYNAMIC & OF_DETACHED bits set.
*
* Return: The newly allocated node or NULL on out of memory error.
* Return: The newly allocated node or NULL on out of memory error. Use
* of_node_put() on it when done to free the memory allocated for it.
*/
struct device_node *__of_node_dup(const struct device_node *np,
const char *full_name)
......
......@@ -100,6 +100,17 @@ struct of_reconfig_data {
struct property *old_prop;
};
/**
* of_node_init - initialize a devicetree node
* @node: Pointer to device node that has been created by kzalloc()
* @phandle_name: Name of property holding a phandle value
*
* On return the device_node refcount is set to one. Use of_node_put()
* on @node when done to free the memory allocated for it. If the node
* is NOT a dynamic node the memory will not be freed. The decision of
* whether to free the memory will be done by node->release(), which is
* of_node_release().
*/
/* initialize a node */
extern const struct kobj_type of_node_ktype;
extern const struct fwnode_operations of_fwnode_ops;
......
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