Commit d9b1103b authored by Daniel Scally's avatar Daniel Scally Committed by Mauro Carvalho Chehab

media: software_node: Enforce parent before child ordering of nodes arrays

Registering software_nodes with the .parent member set to point to a
currently unregistered software_node has the potential for problems,
so enforce parent -> child ordering in arrays passed in to
software_node_register_nodes().

Software nodes that are children of another software node should be
unregistered before their parent. To allow easy unregistering of an array
of software_nodes ordered parent to child, reverse the order in which
software_node_unregister_nodes() unregisters software_nodes.
Suggested-by: default avatarAndy Shevchenko <andriy.shevchenko@linux.intel.com>
Reviewed-by: default avatarLaurent Pinchart <laurent.pinchart@ideasonboard.com>
Signed-off-by: default avatarDaniel Scally <djrscally@gmail.com>
Reviewed-by: default avatarHeikki Krogerus <heikki.krogerus@linux.intel.com>
Acked-by: default avatarGreg Kroah-Hartman <gregkh@linuxfoundation.org>
Acked-by: default avatarRafael J. Wysocki <rafael.j.wysocki@intel.com>
Signed-off-by: default avatarSakari Ailus <sakari.ailus@linux.intel.com>
Signed-off-by: default avatarMauro Carvalho Chehab <mchehab+huawei@kernel.org>
parent acd418bf
......@@ -692,7 +692,11 @@ swnode_register(const struct software_node *node, struct swnode *parent,
* software_node_register_nodes - Register an array of software nodes
* @nodes: Zero terminated array of software nodes to be registered
*
* Register multiple software nodes at once.
* Register multiple software nodes at once. If any node in the array
* has its .parent pointer set (which can only be to another software_node),
* then its parent **must** have been registered before it is; either outside
* of this function or by ordering the array such that parent comes before
* child.
*/
int software_node_register_nodes(const struct software_node *nodes)
{
......@@ -700,14 +704,23 @@ int software_node_register_nodes(const struct software_node *nodes)
int i;
for (i = 0; nodes[i].name; i++) {
ret = software_node_register(&nodes[i]);
if (ret) {
software_node_unregister_nodes(nodes);
return ret;
const struct software_node *parent = nodes[i].parent;
if (parent && !software_node_to_swnode(parent)) {
ret = -EINVAL;
goto err_unregister_nodes;
}
ret = software_node_register(&nodes[i]);
if (ret)
goto err_unregister_nodes;
}
return 0;
err_unregister_nodes:
software_node_unregister_nodes(nodes);
return ret;
}
EXPORT_SYMBOL_GPL(software_node_register_nodes);
......@@ -715,18 +728,23 @@ EXPORT_SYMBOL_GPL(software_node_register_nodes);
* software_node_unregister_nodes - Unregister an array of software nodes
* @nodes: Zero terminated array of software nodes to be unregistered
*
* Unregister multiple software nodes at once.
* Unregister multiple software nodes at once. If parent pointers are set up
* in any of the software nodes then the array **must** be ordered such that
* parents come before their children.
*
* NOTE: Be careful using this call if the nodes had parent pointers set up in
* them before registering. If so, it is wiser to remove the nodes
* individually, in the correct order (child before parent) instead of relying
* on the sequential order of the list of nodes in the array.
* NOTE: If you are uncertain whether the array is ordered such that
* parents will be unregistered before their children, it is wiser to
* remove the nodes individually, in the correct order (child before
* parent).
*/
void software_node_unregister_nodes(const struct software_node *nodes)
{
int i;
unsigned int i = 0;
while (nodes[i].name)
i++;
for (i = 0; nodes[i].name; i++)
while (i--)
software_node_unregister(&nodes[i]);
}
EXPORT_SYMBOL_GPL(software_node_unregister_nodes);
......
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