[PATCH] s390: memory detection > 32GB

The kernel takes a very long time to boot if the memory size is bigger then
32767 MB.  The memory size is contained in a structure created by an sclp
call.  The kernel accesses the field with a LH instrution which performs a
sign extension of a 16 bit word.  In the case of a memory size with bit 2^15
set this results in a very large value and the memory detection just loops for
a long time.  In addition if more then 64 GB are used on a 64 bit system the
memory size is read from an incorrect storage location.

Use zero-extention to read the 16 bit memory size and the correct offset to
read the 4 byte memory size on 64 bit.
Signed-off-by: Martin Schwidefsky <schwidefsky@de.ibm.com>
Signed-off-by: Andrew Morton <akpm@osdl.org>
Signed-off-by: Linus Torvalds <torvalds@osdl.org>

arch/s390/kernel/head.S

@@ -517,10 +517,10 @@ startup:basr  %r13,0                     # get base
 	l     %r2, .Lrcp2-.LPG1(%r13)	# try with Read SCP
 	b     .Lservicecall-.LPG1(%r13)
 .Lprocsccb:
-	lh    %r1,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
-	chi   %r1,0x00
-	jne   .Lscnd
-	l     %r1,.Lscpincr2-PARMAREA(%r4) # otherwise use this one
+	lhi   %r1,0
+	icm   %r1,3,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
+	jnz   .Lscnd
+	l     %r1,.Lscpincr2-PARMAREA+4(%r4) # otherwise use this one
 .Lscnd:
 	xr    %r3,%r3			# same logic
 	ic    %r3,.Lscpa1-PARMAREA(%r4)

arch/s390/kernel/head64.S

@@ -518,9 +518,9 @@ startup:basr  %r13,0                     # get base
 	l     %r2,.Lrcp2-.LPG1(%r13)	# try with Read SCP
 	b     .Lservicecall-.LPG1(%r13)
 .Lprocsccb:
-	lh    %r1,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
-	chi   %r1,0x00
-	jne   .Lscnd
+	lghi  %r1,0
+	icm   %r1,3,.Lscpincr1-PARMAREA(%r4) # use this one if != 0
+	jnz   .Lscnd
 	lg    %r1,.Lscpincr2-PARMAREA(%r4) # otherwise use this one
 .Lscnd:
 	xr    %r3,%r3			# same logic