Commit 2f8f9ff5 authored by John Esmet's avatar John Esmet Committed by Yoni Fogel

refs #5776 merge a fix for 5776 to main. will resolve as closed once 5771 can...

refs #5776 merge a fix for 5776 to main. will resolve as closed once 5771 can survive stress tests for 24 hours or so.


git-svn-id: file:///svn/toku/tokudb@50967 c7de825b-a66e-492c-adef-691d508d4ae1
parent 9ceb4d33
......@@ -138,15 +138,50 @@ void locktree::manager::reference_lt(locktree *lt) {
void locktree::manager::release_lt(locktree *lt) {
bool do_destroy = false;
// decrement using a thread safe sync fetch and sub,
// but double check for a zero ref count using the
// mutex so we serialize with get_lt()
DICTIONARY_ID dict_id = lt->m_dict_id;
// Release a reference on the locktree. If the count transitions to zero,
// then we *may* need to do the cleanup.
//
// Grab the manager's mutex and look for a locktree with this locktree's
// dictionary id. Since dictionary id's never get reused, any locktree
// found must be the one we just released a reference on.
//
// At least two things could have happened since we got the mutex:
// - Another thread gets a locktree with the same dict_id, increments
// the reference count. In this case, we shouldn't destroy it.
// - Another thread gets a locktree with the same dict_id and then
// releases it quickly, transitioning the reference count from zero to
// one and back to zero. In this case, only one of us should destroy it.
// It doesn't matter which. We originally missed this case, see #5776.
//
// After 5776, the high level rule for release is described below.
//
// If a thread releases a locktree and notices the reference count transition
// to zero, then that thread must immediately:
// - assume the locktree object is invalid
// - grab the manager's mutex
// - search the locktree map for a locktree with the same dict_id and remove
// it, if it exists. the destroy may be deferred.
// - release the manager's mutex
//
// This way, if many threads transition the same locktree's reference count
// from 1 to zero and wait behind the manager's mutex, only one of them will
// do the actual destroy and the others will happily do nothing.
uint32_t refs = toku_sync_sub_and_fetch(&lt->m_reference_count, 1);
if (refs == 0) {
mutex_lock();
if (lt->m_reference_count == 0) {
locktree_map_remove(lt);
do_destroy = true;
locktree *find_lt = locktree_map_find(dict_id);
if (find_lt != nullptr) {
// A locktree is still in the map with that dict_id, so it must be
// equal to lt. This is true because dictionary ids are never reused.
// If the reference count is zero, it's our responsibility to remove
// it and do the destroy. Otherwise, someone still wants it.
invariant(find_lt == lt);
if (lt->m_reference_count == 0) {
locktree_map_remove(lt);
do_destroy = true;
}
}
mutex_unlock();
}
......
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