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Kirill Smelkov
mariadb
Commits
84526c67
Commit
84526c67
authored
Oct 31, 2006
by
unknown
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BUG#8804: Better comment + TODO section with suggestion how to speedup
the fix.
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48df3b96
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sql/item_subselect.cc
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sql/item_subselect.cc
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84526c67
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@@ -1946,11 +1946,44 @@ subselect_uniquesubquery_engine::~subselect_uniquesubquery_engine()
...
@@ -1946,11 +1946,44 @@ subselect_uniquesubquery_engine::~subselect_uniquesubquery_engine()
full_scan
full_scan
DESCRIPTION
DESCRIPTION
Resolve subquery using index lookup(s).
The engine is used to resolve subqueries in form
First look for specified constant,
If not found and we need to check for NULLs, do that too.
oe IN (SELECT key FROM tbl WHERE subq_where)
The value of the predicate is calculated as follows:
1. If oe IS NULL, this is a special case, do a full table scan on
table tbl and search for row that satisfies subq_where. If such
row is found, return NULL, otherwise return FALSE.
2. Make an index lookup via key=oe, search for a row that satisfies
subq_where. If found, return TRUE.
3. If check_null==TRUE, make another lookup via key=NULL, search for a
row that satisfies subq_where. If found, return NULL, otherwise
return FALSE.
TODO
The step #1 can be optimized further when the index has several key
parts. Consider a subquery:
(oe1, oe2) IN (SELECT keypart1, keypart2 FROM tbl WHERE subq_where)
and suppose we need to evaluate it for {oe1, oe2}=={const1, NULL}.
Current code will do a full table scan and obtain correct result. There
is a better option: instead of evaluating
SELECT keypart1, keypart2 FROM tbl WHERE subq_where (1)
and checking if it has produced any matching rows, evaluate
SELECT keypart2 FROM tbl WHERE subq_where AND keypart1=const1 (2)
If this query produces a row, the result is NULL (as we're evaluating
"(const1, NULL) IN { (const1, X), ... }", which has a value of UNKNOWN,
i.e. NULL). If the query produces no rows, the result is FALSE.
NULL IN (SELECT ...) is a special case.
We currently evaluate (1) by doing a full table scan. (2) can be
evaluated by doing a "ref" scan on "keypart1=const1", which can be much
cheaper. We can use index statistics to quickly check whether "ref" scan
will be cheaper than full table scan.
RETURN
RETURN
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