Commit a882f7e6 authored by Ramil Kalimullin's avatar Ramil Kalimullin

Fix for bug#52051: Aggregate functions incorrectly returns

      NULL from outer join query
      
      Problem: optimising MIN/MAX() queries without GROUP BY clause
      by replacing the aggregate expression with a constant, we may set it
      to NULL disregarding the fact that there may be outer joins involved.
      
      Fix: don't replace MIN/MAX() with NULL if there're outer joins.
      
      Note: the fix itself is just
      - if (!count)
      + if (!count && !outer_tables)
          set to NULL
      
      The rest of the patch eliminates repeated code to improve speed
      and for easy maintenance of the code.
parent 44fe4c70
......@@ -1790,4 +1790,24 @@ aa b COUNT( b)
1 10 1
DROP TABLE t1, t2;
#
# Bug#52051: Aggregate functions incorrectly returns NULL from outer
# join query
#
CREATE TABLE t1 (a INT PRIMARY KEY);
CREATE TABLE t2 (a INT PRIMARY KEY);
INSERT INTO t2 VALUES (1), (2);
EXPLAIN SELECT MIN(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE NULL NULL NULL NULL NULL NULL NULL Select tables optimized away
SELECT MIN(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
MIN(t2.a)
1
EXPLAIN SELECT MAX(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
id select_type table type possible_keys key key_len ref rows Extra
1 SIMPLE NULL NULL NULL NULL NULL NULL NULL Select tables optimized away
SELECT MAX(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
MAX(t2.a)
2
DROP TABLE t1, t2;
#
# End of 5.1 tests
......@@ -1205,6 +1205,21 @@ SELECT (SELECT t2.a FROM t2 WHERE t2.a = t1.a) aa, b, COUNT( b)
DROP TABLE t1, t2;
--echo #
--echo # Bug#52051: Aggregate functions incorrectly returns NULL from outer
--echo # join query
--echo #
CREATE TABLE t1 (a INT PRIMARY KEY);
CREATE TABLE t2 (a INT PRIMARY KEY);
INSERT INTO t2 VALUES (1), (2);
EXPLAIN SELECT MIN(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
SELECT MIN(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
EXPLAIN SELECT MAX(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
SELECT MAX(t2.a) FROM t2 LEFT JOIN t1 ON t2.a = t1.a;
DROP TABLE t1, t2;
--echo #
--echo # End of 5.1 tests
This diff is collapsed.
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment