Commit b561a98a authored by Sergei Petrunia's avatar Sergei Petrunia

MDEV-406: ANALYZE $stmt: add some tests for joins

parent 7711999d
...@@ -115,5 +115,35 @@ analyze select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b; ...@@ -115,5 +115,35 @@ analyze select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b;
id select_type table type possible_keys key key_len ref rows r_rows filtered r_filtered Extra id select_type table type possible_keys key key_len ref rows r_rows filtered r_filtered Extra
1 SIMPLE t0 ALL NULL NULL NULL NULL 10 10 100.00 50.00 Using where 1 SIMPLE t0 ALL NULL NULL NULL NULL 10 10 100.00 50.00 Using where
1 SIMPLE t1 ALL NULL NULL NULL NULL 10 10 100.00 10.00 Using where; Using join buffer (flat, BNL join) 1 SIMPLE t1 ALL NULL NULL NULL NULL 10 10 100.00 10.00 Using where; Using join buffer (flat, BNL join)
drop table t0,t1;
# TODO: Check what is counted for "range checked for each record". # TODO: Check what is counted for "range checked for each record".
#
# Test for joins
#
create table t2 (key1 int, key2x int, col1 int, key(key1), key(key2x));
insert into t2 select A.a + 10 *B.a +100 * C.a,
(A.a + 10 *B.a +100 * C.a)*2,
A.a + 10 *B.a +100 * C.a
from t0 A, t0 B, t0 C;
# This always has matches, filtered=100%.
analyze select * from t1,t2 where t2.key1=t1.a;
id select_type table type possible_keys key key_len ref rows r_rows filtered r_filtered Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 10 10 100.00 100.00 Using where
1 SIMPLE t2 ref key1 key1 5 test.t1.a 1 1 100.00 100.00
# This shows r_rows=0. It is actually 0.5 (should r_rows be changed to double?)
analyze select * from t1,t2 where t2.key2x=t1.a;
id select_type table type possible_keys key key_len ref rows r_rows filtered r_filtered Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 10 10 100.00 100.00 Using where
1 SIMPLE t2 ref key2x key2x 5 test.t1.a 1 0 100.00 100.00
select * from t1,t2 where t2.key2x=t1.a;
a b key1 key2x col1
0 0 0 0 0
2 2 1 2 1
4 4 2 4 2
6 6 3 6 3
8 8 4 8 4
# This has t2.filtered=40% (there are 5 values: {0,1,2,3,4}. two of them have mod=0)
analyze select * from t1,t2 where t2.key2x=t1.a and mod(t2.col1,4)=0;
id select_type table type possible_keys key key_len ref rows r_rows filtered r_filtered Extra
1 SIMPLE t1 ALL NULL NULL NULL NULL 10 10 100.00 100.00 Using where
1 SIMPLE t2 ref key2x key2x 5 test.t1.a 1 0 100.00 40.00 Using where
drop table t0,t1,t2;
...@@ -84,7 +84,26 @@ explain select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b; ...@@ -84,7 +84,26 @@ explain select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b;
--echo # Now, t1 should have filtered=10 --echo # Now, t1 should have filtered=10
analyze select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b; analyze select * from t0, t1 where t0.a<5 and t1.a<5 and t1.b=t0.b;
drop table t0,t1;
--echo # TODO: Check what is counted for "range checked for each record". --echo # TODO: Check what is counted for "range checked for each record".
--echo #
--echo # Test for joins
--echo #
create table t2 (key1 int, key2x int, col1 int, key(key1), key(key2x));
insert into t2 select A.a + 10 *B.a +100 * C.a,
(A.a + 10 *B.a +100 * C.a)*2,
A.a + 10 *B.a +100 * C.a
from t0 A, t0 B, t0 C;
--echo # This always has matches, filtered=100%.
analyze select * from t1,t2 where t2.key1=t1.a;
--echo # This shows r_rows=0. It is actually 0.5 (should r_rows be changed to double?)
analyze select * from t1,t2 where t2.key2x=t1.a;
select * from t1,t2 where t2.key2x=t1.a;
--echo # This has t2.filtered=40% (there are 5 values: {0,1,2,3,4}. two of them have mod=0)
analyze select * from t1,t2 where t2.key2x=t1.a and mod(t2.col1,4)=0;
drop table t0,t1,t2;
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