select value,description,COUNT(bug_id) from t2 left join t1 on t2.program=t1.product and t2.value=t1.component where program="AAAAA" group by value having COUNT(bug_id) IN (0,2);
value description COUNT(bug_id)
BBBBBBBBBBBBB - conversion 2
BBBBBBBBBBBBB - eeeeeeeee 0
BBBBBBBBBBBBB - generic 2
Documentation 0
Host communication 0
Test Procedures 0
drop table t1,t2;
create table t1 (foo int);
insert into t1 values (1);
...
...
@@ -232,6 +240,13 @@ userid count(*)
3 3
2 1
1 2
select userid,count(*) from t1 group by userid desc having (count(*)+1) IN (4,3);
userid count(*)
3 3
1 2
select userid,count(*) from t1 group by userid desc having 3 IN (1,COUNT(*));
userid count(*)
3 3
explain select spid,count(*) from t1 where spid between 1 and 2 group by spid desc;
table type possible_keys key key_len ref rows Extra
t1 range spID spID 5 NULL 2 Using where; Using index