Commit d190cae0 authored by unknown's avatar unknown

Fix old typo.

parent 655bb9a3
......@@ -33409,7 +33409,7 @@ mysql> SELECT COUNT(DISTINCT results) FROM student;
In MySQL you can get the number of distinct expression
combinations that don't contain NULL by giving a list of expressions.
In ANSI SQL you would have to do a concatenation of all expressions
inside @code{CODE(DISTINCT ...)}.
inside @code{COUNT(DISTINCT ...)}.
@findex AVG()
@item AVG(expr)
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