Backport of: olav.sandstaa@oracle.com-20120516074923-vd0dhp183vqcp2ql
.. into MariaDB 5.3 Fix for Bug#12667154 SAME QUERY EXEC AS WHERE SUBQ GIVES DIFFERENT RESULTS ON IN() & NOT IN() COMP #3 This bug causes a wrong result in mysql-trunk when ICP is used and bad performance in mysql-5.5 and mysql-trunk. Using the query from bug report to explain what happens and causes the wrong result from the query when ICP is enabled: 1. The t3 table contains four records. The outer query will read these and for each of these it will execute the subquery. 2. Before the first execution of the subquery it will be optimized. In this case the important is what happens to the first table t1: -make_join_select() will call the range optimizer which decides that t1 should be accessed using a range scan on the k1 index It creates a QUICK_RANGE_SELECT object for this. -As the last part of optimization the ICP code pushes the condition down to the storage engine for table t1 on the k1 index. This produces the following information in the explain for this table: 2 DEPENDENT SUBQUERY t1 range k1 k1 5 NULL 3 Using index condition; Using filesort Note the use of filesort. 3. The first execution of the subquery does (among other things) due to the need for sorting: a. Call create_sort_index() which again will call find_all_keys(): b. find_all_keys() will read the required keys for all qualifying rows from the storage engine. To do this it checks if it has a quick-select for the table. It will use the quick-select for reading records. In this case it will read four records from the storage engine (based on the range criteria). The storage engine will evaluate the pushed index condition for each record. c. At the end of create_sort_index() there is code that cleans up a lot of stuff on the join tab. One of the things that is cleaned is the select object. The result of this is that the quick-select object created in make_join_select is deleted. 4. The second execution of the subquery does the same as the first but the result is different: a. Call create_sort_index() which again will call find_all_keys() (same as for the first execution) b. find_all_keys() will read the keys from the storage engine. To do this it checks if it has a quick-select for the table. Now there is NO quick-select object(!) (since it was deleted in step 3c). So find_all_keys defaults to read the table using a table scan instead. So instead of reading the four relevant records in the range it reads the entire table (6 records). It then evaluates the table's condition (and here it goes wrong). Since the entire condition has been pushed down to the storage engine using ICP all 6 records qualify. (Note that the storage engine will not evaluate the pushed index condition in this case since it was pushed for the k1 index and now we do a table scan without any index being used). The result is that here we return six qualifying key values instead of four due to not evaluating the table's condition. c. As above. 5. The two last execution of the subquery will also produce wrong results for the same reason. Summary: The problem occurs due to all but the first executions of the subquery is done as a table scan without evaluating the table's condition (which is pushed to the storage engine on a different index). This is caused by the create_sort_index() function deleting the quick-select object that should have been used for executing the subquery as a range scan. Note that this bug in addition to causing wrong results also can result in bad performance due to executing the subquery using a table scan instead of a range scan. This is an issue in MySQL 5.5. The fix for this problem is to avoid that the Quick-select-object that the optimizer created is deleted when create_sort_index() is doing clean-up of the join-tab. This will ensure that the quick-select object and the corresponding pushed index condition will be available and used by all following executions of the subquery.
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