Commit f5e06429 authored by unknown's avatar unknown

cheat when all parts of count(distinct) key are binary

parent 7a852064
......@@ -926,15 +926,26 @@ bool Item_sum_count_distinct::setup(THD *thd)
}
else // too bad, cannot cheat - there is more than one field
{
cmp_arg = (void*)this;
compare_key = (qsort_cmp2)composite_key_cmp;
bool all_binary = 1;
Field** field, **field_end;
field_end = (field = table->field) + table->fields;
for(key_len = 0; field < field_end; ++field)
{
key_len += (*field)->field_length;
if(!(*field)->binary())
all_binary = 0;
}
rec_offset = table->reclength - key_len;
if(all_binary)
{
compare_key = (qsort_cmp2)simple_raw_key_cmp;
cmp_arg = (void*)key_len;
}
else
{
compare_key = (qsort_cmp2)composite_key_cmp ;
cmp_arg = (void*)this;
}
}
init_tree(&tree, min(max_heap_table_size, sortbuff_size/16),
......
Markdown is supported
0%
or
You are about to add 0 people to the discussion. Proceed with caution.
Finish editing this message first!
Please register or to comment