• Kai Germaschewski's avatar
    Handle $(export-objs) ambiguity · e13a5e16
    Kai Germaschewski authored
    We use the makefile variable $(foo-objs) to list the objects
    a composed module foo.o is supposed to be composed of.
    
    We use the special varible $(export-objs) to list the object files which
    export symbols.
    
    This oviously clashes in the case of foo == export. There's basically
    two ways to handle it: (1) rename one of these options, like 
    foo-objs to foo-parts or something, or (2) simply disallow a composite
    object called export.o, so you never need $(export-objs) to list its
    parts.
    
    As (1) would affect basically all Makefiles in the tree and (2) doesn't
    seem much of a limitation, I went for (2).
    e13a5e16
Rules.make 10.5 KB