PCI: Remove struct pci_vpd_ops.release function pointer

The struct pci_vpd_ops.release function pointer is always
pci_vpd_pci22_release(), so there's no need for the flexibility of a
function pointer.

Inline the pci_vpd_pci22_release() body into pci_vpd_release() and remove
pci_vpd_pci22_release() and the struct pci_vpd_ops.release function
pointer.
Tested-by: Shane Seymour <shane.seymour@hpe.com>
Tested-by: Babu Moger <babu.moger@oracle.com>
Signed-off-by: Bjorn Helgaas <bhelgaas@google.com>
Reviewed-by: Hannes Reinecke <hare@suse.com>

drivers/pci/access.c

@@ -508,15 +508,9 @@ static ssize_t pci_vpd_pci22_write(struct pci_dev *dev, loff_t pos, size_t count
 	return ret ? ret : count;
 }
 
-static void pci_vpd_pci22_release(struct pci_dev *dev)
-{
-	kfree(container_of(dev->vpd, struct pci_vpd_pci22, base));
-}
-
 static const struct pci_vpd_ops pci_vpd_pci22_ops = {
 	.read = pci_vpd_pci22_read,
 	.write = pci_vpd_pci22_write,
-	.release = pci_vpd_pci22_release,
 };
 
 static ssize_t pci_vpd_f0_read(struct pci_dev *dev, loff_t pos, size_t count,
@@ -552,7 +546,6 @@ static ssize_t pci_vpd_f0_write(struct pci_dev *dev, loff_t pos, size_t count,
 static const struct pci_vpd_ops pci_vpd_f0_ops = {
 	.read = pci_vpd_f0_read,
 	.write = pci_vpd_f0_write,
-	.release = pci_vpd_pci22_release,
 };
 
 int pci_vpd_pci22_init(struct pci_dev *dev)
@@ -584,7 +577,7 @@ int pci_vpd_pci22_init(struct pci_dev *dev)
 void pci_vpd_release(struct pci_dev *dev)
 {
 	if (dev->vpd)
-		dev->vpd->ops->release(dev);
+		kfree(container_of(dev->vpd, struct pci_vpd_pci22, base));
 }
 
 /**

drivers/pci/pci.h

@@ -97,7 +97,6 @@ static inline bool pci_has_subordinate(struct pci_dev *pci_dev)
 struct pci_vpd_ops {
 	ssize_t (*read)(struct pci_dev *dev, loff_t pos, size_t count, void *buf);
 	ssize_t (*write)(struct pci_dev *dev, loff_t pos, size_t count, const void *buf);
-	void (*release)(struct pci_dev *dev);
 };
 
 struct pci_vpd {